@Niphlod, @LightDot, thanks a lot :) The script I'm referring to parses 10 different RSS feeds at once and stores news (only the latest ones) into the database. Parsing takes around 20-30 s, plus there's bulk_insert() performed. I was wondering to put the script to sleep everytime it finishes parsing a specific feed and inserts results into the db. I guess I'll really start to worry when there's actually something to worry (e.g. high server load).
On Monday, September 30, 2013 1:58:32 PM UTC+2, LightDot wrote: > > @lesssugar Define efficient. :) Are you after a shorter overall execution > time for this task, lower server load, lower power consumption etc.? > > I would generally start the task and leave the management to the database > backend, kernel governor, etc. unless there is a specific need that they > can't provide for. > > Compulsory xkcd <http://xkcd.com/1205/>. And how ever efficient you are, > you're still contributing towards the heat death of the universe, or so > we're told. So theoretically... don't bother unless you need to. > > Regards > > On Monday, September 30, 2013 2:29:57 AM UTC+2, lesssugar wrote: >> >> That was a theoretical question. I'm asking because I don't know which >> approach is better. There's no specific issue I'm trying to address. I just >> want to find out which way is more efficient. > > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
