I have updated new code and it's work. Thanks.
Vào 21:28:22 UTC+7 Thứ tư, ngày 25 tháng chín năm 2013, Massimo Di Pierro
đã viết:
>
> I am using the code in trunk and this work:
>
> # in controller
> @service.xmlrpc
> def add(a,b): return a+b
> def call(): return service()
>
> # in shell
> >>> import xmlrpclib
> >>> s = xmlrpclib.ServerProxy('
> http://127.0.0.1:8000/test/default/call/xmlrpc')
> >>> s.add(3,4)
> 7
>
>
> On Wednesday, 25 September 2013 01:08:49 UTC-5, IVINH wrote:
>>
>> Yes, it's work fine on 2.4.5.
>>
>> Vào 10:41:29 UTC+7 Thứ tư, ngày 25 tháng chín năm 2013, Massimo Di Pierro
>> đã viết:
>>>
>>> Did you define the function ?
>>>
>>> @servicex.xmlrpc
>>> def add(a,b): return a+b
>>>
>>>
>>> On Tuesday, 24 September 2013 20:26:01 UTC-5, IVINH wrote:
>>>>
>>>> I find this with web2py 2.6.4:
>>>>
>>>> >>> s = ServerProxy('http://127.0.0.1:8000/app/default/call/xmlrpc')
>>>> >>> print s.add(3,4)
>>>> Traceback (most recent call last):
>>>> File "<stdin>", line 1, in <module>
>>>> File "C:\Python27\lib\xmlrpclib.py", line 1224, in __call__
>>>> return self.__send(self.__name, args)
>>>> File "C:\Python27\lib\xmlrpclib.py", line 1578, in __request
>>>> verbose=self.__verbose
>>>> File "C:\Python27\lib\xmlrpclib.py", line 1264, in request
>>>> return self.single_request(host, handler, request_body, verbose)
>>>> File "C:\Python27\lib\xmlrpclib.py", line 1312, in single_request
>>>> response.msg,
>>>> xmlrpclib.ProtocolError: <ProtocolError for
>>>> 127.0.0.1:8000/app/default/call/xmlrpc: 500 INTERNAL SERVER ERROR>
>>>>
>>>
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