I think by this:

x = ['a', 'b', 'c', ...]
queries.append(db.mytable.myfield.contains(x))

you mean:

x = ['a', 'b', 'c', ...]
queries.append(db.mytable.myfield.belongs(x))

You cannot pass a list to contains. That may part of the problem.
there may be other problems. Can you show more code or explain what the 
query is supposed to do?

Massimo


On Saturday, 17 August 2013 21:11:52 UTC-5, dave wrote:
>
> I guess nobody encountered this issue before?
>
> On Thursday, August 15, 2013 11:59:31 AM UTC-7, dave wrote:
>>
>> .
>> .
>> .
>> x = ['a', 'b', 'c', ...]
>> queries.append(db.mytable.myfield.contains(x))
>> query = reduce(lambda a,b:(a&b),queries)
>> grid = SQLFORM.grid(query, ...)
>>
>> return (grid=grid)
>>
>> gives an error of "Query Not Supported: parser stack overflow", if the 
>> list x has too many values, like around 100 or a 1000, I suspect its an 
>> sqlite limitation? can anyone suggest another succinct way of passing a 
>> list to a contain like operator or method. 
>>
>

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