Apparently something is not correct as I cannot figure out what the syntax
erro is based on the example you gave here.
This is what I have:
Field('patient name', db.linked patient, represent=lambda c, row:first_name
of patient(c), requires=IS_IN_DB(db,'field.id','%(patient)s')),
On Wed, Jun 26, 2013 at 2:49 AM, Rohitraj Sharma <
rohitraj.sha...@themislexsol.com> wrote:
> You can use labda function in your db
>
> Field('companyField name',db.linked table name, represent=lambda c,
> row:field name of linked table(c), requires=IS_IN_DB(db,'field.id
> ','%(patient)s')),
>
>
> On Wednesday, 26 June 2013 10:36:03 UTC+5:30, Tom Russell wrote:
>>
>> Another question on the smartgrid.
>>
>> I have linked tables in my smartgrid like:
>>
>> grid = SQLFORM.smartgrid(db.patient, deletable=True, editable=True,
>> create=False, maxtextlength=64, paginate=25, links=links,
>> links_in_grid=True, linked_tables=['**emergencycontacts','**
>> dependents'])
>>
>> When clicking on the linked table it shows the id of patient since thats
>> what reference but how can I show the name of the patient rather than the
>> id of patient?
>>
>> Thanks,
>>
>> Tom
>>
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