Sure. To avoid packing it all into a lambda, I would create a separate
function:
def rsa_represent(id, row):
record = db((db.RelationshipSubjectArea.id == id) &
(db.RelationshipSubjectArea.subjectAreaID == db.SubjectArea.
id)).select().first()
return '%s %s' % (record.SubjectArea.subjectAreaCode, record.
RelationshipSubjectArea.relationshipCode)
db.RelationshipRole.relationshipSubjectAreaID.represent = rsa_represent
I will leave it as an exercise to do it using recursive selects. ;-)
Anthony
On Wednesday, May 22, 2013 5:26:49 PM UTC-4, Alex Glaros wrote:
>
> Anthony,
>
> Is there a way to concatenate two "represent" fields for
> db.RelationshipSubjectArea: '%(subjectAreaCode)s %(relationshipCode)' in
> your statement below:
> db.RelationshipRole.relationshipSubjectAreaID.requires = IS_IN_DB(db,
> 'RelationshipSubjectArea.id', lambda r:
> db.SubjectArea(r.subjectAreaID).subjectAreaCode, zero=T('choose one'))
> OR IN
> db.RelationshipRole.relationshipSubjectAreaID.represent = lambda id, r:
> db((db.RelationshipSubjectArea.id == id) &
> (db.RelationshipSubjectArea.subjectAreaID == db.SubjectArea.id
> )).select().first().SubjectArea.subjectAreaCode
>
> The reason is that the other field, relationshipCode (e.g., "Employer and
> Employee" value), needs to be displayed for users to understand which
> choice they're making. See attached image.
>
> Thanks for your comprehensive answers already provided!
>
> I appreciate you reading through the many record relations and providing
> detailed examples.
>
> Your solutions work great.
>
> Alex
>
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