I changed the order as you suggested and no longer get this error:

<type 'exceptions.AttributeError'> 'DAL' object has no attribute 
'DictionaryType'

thanks for that tip

But the error below sill exists

<type 'exceptions.TypeError'> <lambda>() takes exactly 2 arguments (1 given)

thanks,

Alex


On Saturday, February 23, 2013 1:18:20 PM UTC-8, Jim S wrote:
>
> Does it occur after the definition of db.DictionaryType in your model file?
>
> Sorry for the dumb questions, just going over mistakes I've made in the 
> past...
>
> -Jim
>
>
> On Sat, Feb 23, 2013 at 2:09 PM, Alex Glaros <alexg...@gmail.com<javascript:>
> > wrote:
>
>> db.define_table('Word',
>> Field('wordName','string'), 
>> Field ('definition', 'string'), 
>> Field('languageID','reference HumanLanguage'),
>> Field('dictionaryTypeID',*db.DictionaryType*),
>> Field('wordReferenceModelID','reference WordReferenceModel'), 
>> Field('comments','string'), auth.signature)
>>
>> On Sat, Feb 23, 2013 at 12:01 PM, Jim Steil <ato....@gmail.com<javascript:>
>> > wrote:
>>
>>>
>>> Can you paste the table definition that choked on you?
>>>
>>> -Jim
>>>
>>>
>>> On Sat, Feb 23, 2013 at 1:34 PM, Alex Glaros 
>>> <alexg...@gmail.com<javascript:>
>>> > wrote:
>>>
>>>> web2py doesn't seem to accept that format on my windows version.  I get
>>>>
>>>> <type 'exceptions.AttributeError'> 'DAL' object has no attribute 
>>>> 'DictionaryType' 
>>>> The error below doesn't come up when there is no data:
>>>>
>>>> *<type 'exceptions.TypeError'> <lambda>() takes exactly 2 arguments (1 
>>>> given)*
>>>>
>>>> The represent attribute works if there are two files in play instead of 
>>>> three
>>>>
>>>> I created a simplified version and changed every field name in case 
>>>> there was some reserved word problem but it didn't work
>>>>
>>>> What I will do is write something similar from scratch with different 
>>>> table and field names.
>>>>
>>>> Thanks,
>>>>
>>>> Alex
>>>>
>>>> On Sat, Feb 23, 2013 at 8:35 AM, Jim S <j...@qlf.com <javascript:>>wrote:
>>>>
>>>>> Just to be clear, he isn't asking just to remove quotes, but to 
>>>>> specify your reference columns as:
>>>>>
>>>>> db.table_name
>>>>>
>>>>> instead of
>>>>>
>>>>> 'reference table_name'
>>>>>
>>>>> -Jim
>>>>>
>>>>> On Friday, February 22, 2013 7:14:18 PM UTC-6, Alex Glaros wrote:
>>>>>
>>>>>> thanks for giving it a shot but depending upon whether I use quotes 
>>>>>> or not, either the data column disappears from the web page or I get 
>>>>>> errors
>>>>>>
>>>>>> On Fri, Feb 22, 2013 at 1:47 PM, Kyle Flanagan 
>>>>>> <kylefl...@gmail.com>wrote:
>>>>>>
>>>>>>> Have you tried adding a format to your tables and defining your 
>>>>>>> tables using objects instead of 'reference...'?
>>>>>>>
>>>>>>> I'm no web2py expert by any means, but I had a similar situation and 
>>>>>>> when I changed the reference for my foreign id to db.other_table 
>>>>>>> instead of 
>>>>>>> 'reference other_table,' the format defined for that table was used 
>>>>>>> instead 
>>>>>>> of the id.
>>>>>>>
>>>>>>> Something like this:
>>>>>>> db.define_table('HumanLanguage',
>>>>>>>     Field('languageName','string'),
>>>>>>>     Field('forumLocations','string'),
>>>>>>>
>>>>>>>     Field('comments','string'),
>>>>>>>  
>>>>>>>     format = '%(languageName)s'), # define a format
>>>>>>>     auth.signature)
>>>>>>> db.HumanLanguage.languageName.requires = IS_NOT_EMPTY()
>>>>>>>
>>>>>>> ##
>>>>>>> ## Define DictionaryReferenceModel and WordReferenceModel above here
>>>>>>> ## DictionaryReferenceModel, WordReferenceModel should have a format
>>>>>>> ##
>>>>>>>
>>>>>>>
>>>>>>> ## Dictionary type means what category of dictionary is it? Medical, 
>>>>>>> computer,etc.  There is one for each language.
>>>>>>> db.define_table('DictionaryType',
>>>>>>>
>>>>>>>     Field('dictionaryName','string'),
>>>>>>>
>>>>>>>     Field('comments','string'),
>>>>>>>  
>>>>>>>     Field('languageID',db.HumanLanguage ), # changed to object
>>>>>>>     Field('DictionaryReferenceModelID', db.DictionaryReferenceModel
>>>>>>> ), # changed to object
>>>>>>>     format = '%(dictionaryName)s', # define format
>>>>>>>
>>>>>>>     auth.signature)
>>>>>>> db.DictionaryType.dictionaryName.requires = IS_NOT_EMPTY()
>>>>>>> db.DictionaryType.languageID.requires = IS_IN_DB(db, 
>>>>>>> 'HumanLanguage.id', '%(languageName)s',zero=T('choose one'))
>>>>>>> db.DictionaryType.DictionaryReferenceModelID.requires = IS_IN_DB(db, 
>>>>>>> 'DictionaryReferenceModel.id', '%(DictionaryTypeID)s',zero=T('choose 
>>>>>>> one'))
>>>>>>>
>>>>>>>
>>>>>>> db.define_table('Word',
>>>>>>>
>>>>>>> Field('wordName','string'), 
>>>>>>> Field ('definition','string'), 
>>>>>>> Field('languageID', db.HumanLanguage ), # changed to object
>>>>>>> Field('dictionaryTypeID',db.DictionaryType), # changed to object
>>>>>>> Field('wordReferenceModelID',db.WordReferenceModel), # changed to 
>>>>>>> object
>>>>>>>
>>>>>>> Field('comments','string'), 
>>>>>>> auth.signature)
>>>>>>> db.Word.languageID.requires = IS_IN_DB(db, 'HumanLanguage.id', 
>>>>>>> '%(languageName)s',zero=T('choose one'))
>>>>>>> db.Word.dictionaryTypeID.requires = IS_IN_DB(db, 'DictionaryType.id'
>>>>>>> , '%(dictionaryName)s',zero=T('choose one'))
>>>>>>> db.Word.wordName.requires = IS_NOT_EMPTY()
>>>>>>> db.Word.wordReferenceModelID.requires = IS_NULL_OR(IS_IN_DB(db, 
>>>>>>> 'WordReferenceModel.id', '%(wordID)s',zero=T('choose one')))
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> On Friday, February 22, 2013 2:48:19 PM UTC-6, Alex Glaros wrote:
>>>>>>>>
>>>>>>>> thanks for offering to take a look.  
>>>>>>>>
>>>>>>>> Screen shots here: 
>>>>>>>> https://docs.google.com/document/d/1e517YRN8FK08vqsVWmp1UuZ0LLevCNlkrhWyCkBQ7uQ/edit?usp=sharing
>>>>>>>>
>>>>>>>> Alex
>>>>>>>>
>>>>>>>> On Friday, February 22, 2013 12:16:39 PM UTC-8, Jim S wrote:
>>>>>>>>>
>>>>>>>>> Sorry, I'm kinda lost in what you're trying to do.  Can you show 
>>>>>>>>> it in code or screen shots?
>>>>>>>>>
>>>>>>>>> -Jim
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> On Fri, Feb 22, 2013 at 12:08 PM, Alex Glaros 
>>>>>>>>> <alexg...@gmail.com>wrote:
>>>>>>>>>
>>>>>>>>>> There is a grandparent (HumanLanguage), parent (DictionaryType), 
>>>>>>>>>> child (Word), relationship.  If I go straight from the grandparent 
>>>>>>>>>> to the 
>>>>>>>>>> child, "represent" works.  
>>>>>>>>>> (First I click on HumanLangages, then I click on Word)
>>>>>>>>>>
>>>>>>>>>> If I go from the parent to the child, I get this message: <type 
>>>>>>>>>> 'exceptions.TypeError'> <lambda>() takes exactly 2 arguments (1 
>>>>>>>>>> given)
>>>>>>>>>> (First I click on HumanLangages, then I click on DictionaryType, 
>>>>>>>>>> then, I click on Word)
>>>>>>>>>>
>>>>>>>>>> If I reduce the number of parms 
>>>>>>>>>> to db.Word.dictionaryTypeID.represent = lambda id: 
>>>>>>>>>> db.DictionaryType(id).dictionaryName, then it works if I go from the 
>>>>>>>>>> parent 
>>>>>>>>>> to the child, but if I go from the grandparent to the child, I get 
>>>>>>>>>> <type 
>>>>>>>>>> 'exceptions.TypeError'> <lambda>() takes exactly 1 argument (2 
>>>>>>>>>> given).
>>>>>>>>>>
>>>>>>>>>> If a join was allowed, it would solve the problem but I think 
>>>>>>>>>> they are not supported in smartgrid. 
>>>>>>>>>>
>>>>>>>>>> Any ideas would be much appreciated,
>>>>>>>>>>
>>>>>>>>>> Thanks,
>>>>>>>>>>
>>>>>>>>>> Alex
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> On Friday, February 22, 2013 5:24:48 AM UTC-8, Jim S wrote:
>>>>>>>>>>
>>>>>>>>>>> Depends on whether or not you want that behavior globally or 
>>>>>>>>>>> not.  Remember, your model gets executed on every request.  So, if 
>>>>>>>>>>> you want 
>>>>>>>>>>> that behavior globally I'd put it there.  If you just need it for 
>>>>>>>>>>> one 
>>>>>>>>>>> instance, put it in the controller.
>>>>>>>>>>>
>>>>>>>>>>> -Jim
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> On Fri, Feb 22, 2013 at 12:20 AM, Alex Glaros <
>>>>>>>>>>> alexg...@gmail.com> wrote:
>>>>>>>>>>>
>>>>>>>>>>>> It worked Jim
>>>>>>>>>>>>
>>>>>>>>>>>> thanks so much for going through the process of writing and 
>>>>>>>>>>>> testing the code.
>>>>>>>>>>>>  
>>>>>>>>>>>> I'm new to web2py, is there any preference as to where that 
>>>>>>>>>>>> statement goes: controller or model?
>>>>>>>>>>>>
>>>>>>>>>>>> much appreciated,
>>>>>>>>>>>>
>>>>>>>>>>>> Alex
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> On Thu, Feb 21, 2013 at 8:31 PM, Jim S <j...@qlf.com> wrote:
>>>>>>>>>>>>
>>>>>>>>>>>>> Add this line before creating your smartgrid:
>>>>>>>>>>>>>
>>>>>>>>>>>>> db.Word.dictionaryTypeID.represent = lambda s,r: 
>>>>>>>>>>>>> s.dictionaryName
>>>>>>>>>>>>>
>>>>>>>>>>>>> Does that help?  It worked for the trimmed down model I made...
>>>>>>>>>>>>>
>>>>>>>>>>>>> -Jim
>>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>> On Thursday, February 21, 2013 9:16:39 PM UTC-6, Alex Glaros 
>>>>>>>>>>>>> wrote:
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> db.define_table('HumanLanguage',Field('languageName','string'),Field('forumLocations','string'),Field('comments','string'),
>>>>>>>>>>>>>>  
>>>>>>>>>>>>>> auth.signature)
>>>>>>>>>>>>>> db.HumanLanguage.languageName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> db.define_table('Word',Field('wordName','string'), Field 
>>>>>>>>>>>>>> ('definition', 'string'), Field('languageID','reference 
>>>>>>>>>>>>>> HumanLanguage'),Field('dictionaryTypeID','reference 
>>>>>>>>>>>>>> DictionaryType'),Field('wordReferenceModelID','reference 
>>>>>>>>>>>>>> WordReferenceModel'), Field('comments','string'), auth.signature)
>>>>>>>>>>>>>> db.Word.languageID.requires = IS_IN_DB(db, 
>>>>>>>>>>>>>> 'HumanLanguage.id', '%(languageName)s',zero=T('choose one'))
>>>>>>>>>>>>>> db.Word.dictionaryTypeID.requires = IS_IN_DB(db, 
>>>>>>>>>>>>>> 'DictionaryType.id', '%(dictionaryName)s',zero=T('choose one'))
>>>>>>>>>>>>>> db.Word.wordName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.Word.wordReferenceModelID.requires = 
>>>>>>>>>>>>>> IS_NULL_OR(IS_IN_DB(db, 'WordReferenceModel.id', 
>>>>>>>>>>>>>> '%(wordID)s',zero=T('choose one')))
>>>>>>>>>>>>>>  
>>>>>>>>>>>>>> ## Uses English language as standard connector between all 
>>>>>>>>>>>>>> languages. WordID below points to the English version of the 
>>>>>>>>>>>>>> word that is 
>>>>>>>>>>>>>> the standard. The reason "Is_Null" clause is there is because 
>>>>>>>>>>>>>> the first 
>>>>>>>>>>>>>> time the word is encountered, it won't be in the English 
>>>>>>>>>>>>>> dictionary
>>>>>>>>>>>>>> db.define_table('WordReferenceModel',Field('wordID','reference 
>>>>>>>>>>>>>> Word'),Field('dictionaryTypeID','reference DictionaryType'), 
>>>>>>>>>>>>>> Field('picture', 'upload', 
>>>>>>>>>>>>>> default=''),Field('comments','string'), 
>>>>>>>>>>>>>> auth.signature) 
>>>>>>>>>>>>>> db.WordReferenceModel.wordID.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.WordReferenceModel.wordID.requires = IS_IN_DB(db, 
>>>>>>>>>>>>>> 'Word.id', '%(wordName)s',zero=T('choose one'))
>>>>>>>>>>>>>> db.WordReferenceModel.dictionaryTypeID.requires = 
>>>>>>>>>>>>>> IS_IN_DB(db, 'DictionaryType.id', 
>>>>>>>>>>>>>> '%(dictionaryName)s',zero=T('choose one'))
>>>>>>>>>>>>>> ## dictionary_type_query = 
>>>>>>>>>>>>>> (db.DictionaryType.dictionaryName=='English')
>>>>>>>>>>>>>> ## /* need this too for wordReferenceModel */
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> ## Dictionary type means what category of dictionary is it? 
>>>>>>>>>>>>>> Medical, computer,etc.  There is one for each language.
>>>>>>>>>>>>>> db.define_table('DictionaryType',Field('dictionaryName','string'),Field('comments','string'),
>>>>>>>>>>>>>>  
>>>>>>>>>>>>>> Field('languageID','reference HumanLanguage'),
>>>>>>>>>>>>>>     Field('DictionaryReferenceModelID', 'reference 
>>>>>>>>>>>>>> DictionaryReferenceModel'), auth.signature)
>>>>>>>>>>>>>> db.DictionaryType.dictionaryName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.DictionaryType.languageID.requires = IS_IN_DB(db, 
>>>>>>>>>>>>>> 'HumanLanguage.id', '%(languageName)s',zero=T('choose one'))
>>>>>>>>>>>>>>  db.DictionaryType.DictionaryReferenceModelID.requires = 
>>>>>>>>>>>>>> IS_IN_DB(db, 'DictionaryReferenceModel.id', 
>>>>>>>>>>>>>> '%(DictionaryTypeID)s',zero=T('choose one'))
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> ## Uses English dictionary type as standard connector between 
>>>>>>>>>>>>>> all dictionary types. DictionaryType.id points to the English 
>>>>>>>>>>>>>> DictionaryType.id
>>>>>>>>>>>>>> db.define_table('DictionaryReferenceModel', 
>>>>>>>>>>>>>> Field('DictionaryTypeID','reference 
>>>>>>>>>>>>>> DictionaryType'),Field('comments','string'), 
>>>>>>>>>>>>>>     auth.signature)
>>>>>>>>>>>>>> db.DictionaryReferenceModel.DictionaryTypeID.requires = 
>>>>>>>>>>>>>> IS_NOT_EMPTY()
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> db.define_table('Synonyms',Field('synonymName','string'),Field('wordID','reference
>>>>>>>>>>>>>>  
>>>>>>>>>>>>>> Word'),Field('comments','string'), 
>>>>>>>>>>>>>>     auth.signature)
>>>>>>>>>>>>>> db.Synonyms.synonymName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.Synonyms.wordID.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.Synonyms.wordID.requires = IS_IN_DB(db, 'Word.id', 
>>>>>>>>>>>>>> '%(Word)s',zero=T('choose one'))
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> db.define_table('PublicComments',Field('wordID','reference 
>>>>>>>>>>>>>> Word'),Field('comments','string'), 
>>>>>>>>>>>>>>     auth.signature)
>>>>>>>>>>>>>> db.PublicComments.comments.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.PublicComments.wordID.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.PublicComments.wordID.requires = IS_IN_DB(db, 'Word.id', 
>>>>>>>>>>>>>> '%(wordName)s',zero=T('choose one'))
>>>>>>>>>>>>>>
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> On Thursday, February 21, 2013 6:10:56 PM UTC-8, Jim S wrote:
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Can you show the model code?
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> -Jim
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> On Thursday, February 21, 2013 7:35:52 PM UTC-6, Alex Glaros 
>>>>>>>>>>>>>>> wrote:
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Instead of *db.Word.dictionaryTypeID* displaying (which is 
>>>>>>>>>>>>>>>> a foreign key in db.Word), I’d like a value from the foreign 
>>>>>>>>>>>>>>>> table to 
>>>>>>>>>>>>>>>> appear, i.e., DictionaryType. dictionaryName.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> In the example below, when user cascades down to the Word 
>>>>>>>>>>>>>>>> table, it only shows db.Word.dictionaryTypeID but I’d like to 
>>>>>>>>>>>>>>>> add the 
>>>>>>>>>>>>>>>> corresponding DictionaryType. dictionaryName value to it.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> def search_lang():  
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>    grid = SQLFORM.smartgrid(db.HumanLanguage, 
>>>>>>>>>>>>>>>> linked_tables=['Word','DictionaryType'], fields = [
>>>>>>>>>>>>>>>> db.HumanLanguage.id, db.HumanLanguage.languageName, 
>>>>>>>>>>>>>>>> db.Word.id, db.Word.wordName, db.Word.definition, 
>>>>>>>>>>>>>>>> db.DictionaryType.dictionaryName,
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>        *db.Word.dictionaryTypeID*],
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>        user_signature=False)
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>    return dict(grid=grid)
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> id<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.id>
>>>>>>>>>>>>>>>>   
>>>>>>>>>>>>>>>>   
>>>>>>>>>>>>>>>> Wordname<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.wordName>
>>>>>>>>>>>>>>>>    
>>>>>>>>>>>>>>>>   
>>>>>>>>>>>>>>>> Definition<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.definition>
>>>>>>>>>>>>>>>>   
>>>>>>>>>>>>>>>>   
>>>>>>>>>>>>>>>> Dictionarytypeid<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.dictionaryTypeID>
>>>>>>>>>>>>>>>>  
>>>>>>>>>>>>>>>> 1 beaker    glass jar     1
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Want to replace the "1" under Dictionarytypeid with value 
>>>>>>>>>>>>>>>> from foreign table.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Thanks, 
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Alex Glaros
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> -- 
>>>>>>>>>>>>>  
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>>>>>>>>>>>>>  
>>>>>>>>>>>>>
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