I changed the order as you suggested and no longer get this error:
<type 'exceptions.AttributeError'> 'DAL' object has no attribute
'DictionaryType'
thanks for that tip
But the error below sill exists
<type 'exceptions.TypeError'> <lambda>() takes exactly 2 arguments (1 given)
thanks,
Alex
On Saturday, February 23, 2013 1:18:20 PM UTC-8, Jim S wrote:
>
> Does it occur after the definition of db.DictionaryType in your model file?
>
> Sorry for the dumb questions, just going over mistakes I've made in the
> past...
>
> -Jim
>
>
> On Sat, Feb 23, 2013 at 2:09 PM, Alex Glaros <alexg...@gmail.com<javascript:>
> > wrote:
>
>> db.define_table('Word',
>> Field('wordName','string'),
>> Field ('definition', 'string'),
>> Field('languageID','reference HumanLanguage'),
>> Field('dictionaryTypeID',*db.DictionaryType*),
>> Field('wordReferenceModelID','reference WordReferenceModel'),
>> Field('comments','string'), auth.signature)
>>
>> On Sat, Feb 23, 2013 at 12:01 PM, Jim Steil <ato....@gmail.com<javascript:>
>> > wrote:
>>
>>>
>>> Can you paste the table definition that choked on you?
>>>
>>> -Jim
>>>
>>>
>>> On Sat, Feb 23, 2013 at 1:34 PM, Alex Glaros
>>> <alexg...@gmail.com<javascript:>
>>> > wrote:
>>>
>>>> web2py doesn't seem to accept that format on my windows version. I get
>>>>
>>>> <type 'exceptions.AttributeError'> 'DAL' object has no attribute
>>>> 'DictionaryType'
>>>> The error below doesn't come up when there is no data:
>>>>
>>>> *<type 'exceptions.TypeError'> <lambda>() takes exactly 2 arguments (1
>>>> given)*
>>>>
>>>> The represent attribute works if there are two files in play instead of
>>>> three
>>>>
>>>> I created a simplified version and changed every field name in case
>>>> there was some reserved word problem but it didn't work
>>>>
>>>> What I will do is write something similar from scratch with different
>>>> table and field names.
>>>>
>>>> Thanks,
>>>>
>>>> Alex
>>>>
>>>> On Sat, Feb 23, 2013 at 8:35 AM, Jim S <j...@qlf.com <javascript:>>wrote:
>>>>
>>>>> Just to be clear, he isn't asking just to remove quotes, but to
>>>>> specify your reference columns as:
>>>>>
>>>>> db.table_name
>>>>>
>>>>> instead of
>>>>>
>>>>> 'reference table_name'
>>>>>
>>>>> -Jim
>>>>>
>>>>> On Friday, February 22, 2013 7:14:18 PM UTC-6, Alex Glaros wrote:
>>>>>
>>>>>> thanks for giving it a shot but depending upon whether I use quotes
>>>>>> or not, either the data column disappears from the web page or I get
>>>>>> errors
>>>>>>
>>>>>> On Fri, Feb 22, 2013 at 1:47 PM, Kyle Flanagan
>>>>>> <kylefl...@gmail.com>wrote:
>>>>>>
>>>>>>> Have you tried adding a format to your tables and defining your
>>>>>>> tables using objects instead of 'reference...'?
>>>>>>>
>>>>>>> I'm no web2py expert by any means, but I had a similar situation and
>>>>>>> when I changed the reference for my foreign id to db.other_table
>>>>>>> instead of
>>>>>>> 'reference other_table,' the format defined for that table was used
>>>>>>> instead
>>>>>>> of the id.
>>>>>>>
>>>>>>> Something like this:
>>>>>>> db.define_table('HumanLanguage',
>>>>>>> Field('languageName','string'),
>>>>>>> Field('forumLocations','string'),
>>>>>>>
>>>>>>> Field('comments','string'),
>>>>>>>
>>>>>>> format = '%(languageName)s'), # define a format
>>>>>>> auth.signature)
>>>>>>> db.HumanLanguage.languageName.requires = IS_NOT_EMPTY()
>>>>>>>
>>>>>>> ##
>>>>>>> ## Define DictionaryReferenceModel and WordReferenceModel above here
>>>>>>> ## DictionaryReferenceModel, WordReferenceModel should have a format
>>>>>>> ##
>>>>>>>
>>>>>>>
>>>>>>> ## Dictionary type means what category of dictionary is it? Medical,
>>>>>>> computer,etc. There is one for each language.
>>>>>>> db.define_table('DictionaryType',
>>>>>>>
>>>>>>> Field('dictionaryName','string'),
>>>>>>>
>>>>>>> Field('comments','string'),
>>>>>>>
>>>>>>> Field('languageID',db.HumanLanguage ), # changed to object
>>>>>>> Field('DictionaryReferenceModelID', db.DictionaryReferenceModel
>>>>>>> ), # changed to object
>>>>>>> format = '%(dictionaryName)s', # define format
>>>>>>>
>>>>>>> auth.signature)
>>>>>>> db.DictionaryType.dictionaryName.requires = IS_NOT_EMPTY()
>>>>>>> db.DictionaryType.languageID.requires = IS_IN_DB(db,
>>>>>>> 'HumanLanguage.id', '%(languageName)s',zero=T('choose one'))
>>>>>>> db.DictionaryType.DictionaryReferenceModelID.requires = IS_IN_DB(db,
>>>>>>> 'DictionaryReferenceModel.id', '%(DictionaryTypeID)s',zero=T('choose
>>>>>>> one'))
>>>>>>>
>>>>>>>
>>>>>>> db.define_table('Word',
>>>>>>>
>>>>>>> Field('wordName','string'),
>>>>>>> Field ('definition','string'),
>>>>>>> Field('languageID', db.HumanLanguage ), # changed to object
>>>>>>> Field('dictionaryTypeID',db.DictionaryType), # changed to object
>>>>>>> Field('wordReferenceModelID',db.WordReferenceModel), # changed to
>>>>>>> object
>>>>>>>
>>>>>>> Field('comments','string'),
>>>>>>> auth.signature)
>>>>>>> db.Word.languageID.requires = IS_IN_DB(db, 'HumanLanguage.id',
>>>>>>> '%(languageName)s',zero=T('choose one'))
>>>>>>> db.Word.dictionaryTypeID.requires = IS_IN_DB(db, 'DictionaryType.id'
>>>>>>> , '%(dictionaryName)s',zero=T('choose one'))
>>>>>>> db.Word.wordName.requires = IS_NOT_EMPTY()
>>>>>>> db.Word.wordReferenceModelID.requires = IS_NULL_OR(IS_IN_DB(db,
>>>>>>> 'WordReferenceModel.id', '%(wordID)s',zero=T('choose one')))
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> On Friday, February 22, 2013 2:48:19 PM UTC-6, Alex Glaros wrote:
>>>>>>>>
>>>>>>>> thanks for offering to take a look.
>>>>>>>>
>>>>>>>> Screen shots here:
>>>>>>>> https://docs.google.com/document/d/1e517YRN8FK08vqsVWmp1UuZ0LLevCNlkrhWyCkBQ7uQ/edit?usp=sharing
>>>>>>>>
>>>>>>>> Alex
>>>>>>>>
>>>>>>>> On Friday, February 22, 2013 12:16:39 PM UTC-8, Jim S wrote:
>>>>>>>>>
>>>>>>>>> Sorry, I'm kinda lost in what you're trying to do. Can you show
>>>>>>>>> it in code or screen shots?
>>>>>>>>>
>>>>>>>>> -Jim
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> On Fri, Feb 22, 2013 at 12:08 PM, Alex Glaros
>>>>>>>>> <alexg...@gmail.com>wrote:
>>>>>>>>>
>>>>>>>>>> There is a grandparent (HumanLanguage), parent (DictionaryType),
>>>>>>>>>> child (Word), relationship. If I go straight from the grandparent
>>>>>>>>>> to the
>>>>>>>>>> child, "represent" works.
>>>>>>>>>> (First I click on HumanLangages, then I click on Word)
>>>>>>>>>>
>>>>>>>>>> If I go from the parent to the child, I get this message: <type
>>>>>>>>>> 'exceptions.TypeError'> <lambda>() takes exactly 2 arguments (1
>>>>>>>>>> given)
>>>>>>>>>> (First I click on HumanLangages, then I click on DictionaryType,
>>>>>>>>>> then, I click on Word)
>>>>>>>>>>
>>>>>>>>>> If I reduce the number of parms
>>>>>>>>>> to db.Word.dictionaryTypeID.represent = lambda id:
>>>>>>>>>> db.DictionaryType(id).dictionaryName, then it works if I go from the
>>>>>>>>>> parent
>>>>>>>>>> to the child, but if I go from the grandparent to the child, I get
>>>>>>>>>> <type
>>>>>>>>>> 'exceptions.TypeError'> <lambda>() takes exactly 1 argument (2
>>>>>>>>>> given).
>>>>>>>>>>
>>>>>>>>>> If a join was allowed, it would solve the problem but I think
>>>>>>>>>> they are not supported in smartgrid.
>>>>>>>>>>
>>>>>>>>>> Any ideas would be much appreciated,
>>>>>>>>>>
>>>>>>>>>> Thanks,
>>>>>>>>>>
>>>>>>>>>> Alex
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> On Friday, February 22, 2013 5:24:48 AM UTC-8, Jim S wrote:
>>>>>>>>>>
>>>>>>>>>>> Depends on whether or not you want that behavior globally or
>>>>>>>>>>> not. Remember, your model gets executed on every request. So, if
>>>>>>>>>>> you want
>>>>>>>>>>> that behavior globally I'd put it there. If you just need it for
>>>>>>>>>>> one
>>>>>>>>>>> instance, put it in the controller.
>>>>>>>>>>>
>>>>>>>>>>> -Jim
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> On Fri, Feb 22, 2013 at 12:20 AM, Alex Glaros <
>>>>>>>>>>> alexg...@gmail.com> wrote:
>>>>>>>>>>>
>>>>>>>>>>>> It worked Jim
>>>>>>>>>>>>
>>>>>>>>>>>> thanks so much for going through the process of writing and
>>>>>>>>>>>> testing the code.
>>>>>>>>>>>>
>>>>>>>>>>>> I'm new to web2py, is there any preference as to where that
>>>>>>>>>>>> statement goes: controller or model?
>>>>>>>>>>>>
>>>>>>>>>>>> much appreciated,
>>>>>>>>>>>>
>>>>>>>>>>>> Alex
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> On Thu, Feb 21, 2013 at 8:31 PM, Jim S <j...@qlf.com> wrote:
>>>>>>>>>>>>
>>>>>>>>>>>>> Add this line before creating your smartgrid:
>>>>>>>>>>>>>
>>>>>>>>>>>>> db.Word.dictionaryTypeID.represent = lambda s,r:
>>>>>>>>>>>>> s.dictionaryName
>>>>>>>>>>>>>
>>>>>>>>>>>>> Does that help? It worked for the trimmed down model I made...
>>>>>>>>>>>>>
>>>>>>>>>>>>> -Jim
>>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>> On Thursday, February 21, 2013 9:16:39 PM UTC-6, Alex Glaros
>>>>>>>>>>>>> wrote:
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> db.define_table('HumanLanguage',Field('languageName','string'),Field('forumLocations','string'),Field('comments','string'),
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> auth.signature)
>>>>>>>>>>>>>> db.HumanLanguage.languageName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> db.define_table('Word',Field('wordName','string'), Field
>>>>>>>>>>>>>> ('definition', 'string'), Field('languageID','reference
>>>>>>>>>>>>>> HumanLanguage'),Field('dictionaryTypeID','reference
>>>>>>>>>>>>>> DictionaryType'),Field('wordReferenceModelID','reference
>>>>>>>>>>>>>> WordReferenceModel'), Field('comments','string'), auth.signature)
>>>>>>>>>>>>>> db.Word.languageID.requires = IS_IN_DB(db,
>>>>>>>>>>>>>> 'HumanLanguage.id', '%(languageName)s',zero=T('choose one'))
>>>>>>>>>>>>>> db.Word.dictionaryTypeID.requires = IS_IN_DB(db,
>>>>>>>>>>>>>> 'DictionaryType.id', '%(dictionaryName)s',zero=T('choose one'))
>>>>>>>>>>>>>> db.Word.wordName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.Word.wordReferenceModelID.requires =
>>>>>>>>>>>>>> IS_NULL_OR(IS_IN_DB(db, 'WordReferenceModel.id',
>>>>>>>>>>>>>> '%(wordID)s',zero=T('choose one')))
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> ## Uses English language as standard connector between all
>>>>>>>>>>>>>> languages. WordID below points to the English version of the
>>>>>>>>>>>>>> word that is
>>>>>>>>>>>>>> the standard. The reason "Is_Null" clause is there is because
>>>>>>>>>>>>>> the first
>>>>>>>>>>>>>> time the word is encountered, it won't be in the English
>>>>>>>>>>>>>> dictionary
>>>>>>>>>>>>>> db.define_table('WordReferenceModel',Field('wordID','reference
>>>>>>>>>>>>>> Word'),Field('dictionaryTypeID','reference DictionaryType'),
>>>>>>>>>>>>>> Field('picture', 'upload',
>>>>>>>>>>>>>> default=''),Field('comments','string'),
>>>>>>>>>>>>>> auth.signature)
>>>>>>>>>>>>>> db.WordReferenceModel.wordID.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.WordReferenceModel.wordID.requires = IS_IN_DB(db,
>>>>>>>>>>>>>> 'Word.id', '%(wordName)s',zero=T('choose one'))
>>>>>>>>>>>>>> db.WordReferenceModel.dictionaryTypeID.requires =
>>>>>>>>>>>>>> IS_IN_DB(db, 'DictionaryType.id',
>>>>>>>>>>>>>> '%(dictionaryName)s',zero=T('choose one'))
>>>>>>>>>>>>>> ## dictionary_type_query =
>>>>>>>>>>>>>> (db.DictionaryType.dictionaryName=='English')
>>>>>>>>>>>>>> ## /* need this too for wordReferenceModel */
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> ## Dictionary type means what category of dictionary is it?
>>>>>>>>>>>>>> Medical, computer,etc. There is one for each language.
>>>>>>>>>>>>>> db.define_table('DictionaryType',Field('dictionaryName','string'),Field('comments','string'),
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> Field('languageID','reference HumanLanguage'),
>>>>>>>>>>>>>> Field('DictionaryReferenceModelID', 'reference
>>>>>>>>>>>>>> DictionaryReferenceModel'), auth.signature)
>>>>>>>>>>>>>> db.DictionaryType.dictionaryName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.DictionaryType.languageID.requires = IS_IN_DB(db,
>>>>>>>>>>>>>> 'HumanLanguage.id', '%(languageName)s',zero=T('choose one'))
>>>>>>>>>>>>>> db.DictionaryType.DictionaryReferenceModelID.requires =
>>>>>>>>>>>>>> IS_IN_DB(db, 'DictionaryReferenceModel.id',
>>>>>>>>>>>>>> '%(DictionaryTypeID)s',zero=T('choose one'))
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> ## Uses English dictionary type as standard connector between
>>>>>>>>>>>>>> all dictionary types. DictionaryType.id points to the English
>>>>>>>>>>>>>> DictionaryType.id
>>>>>>>>>>>>>> db.define_table('DictionaryReferenceModel',
>>>>>>>>>>>>>> Field('DictionaryTypeID','reference
>>>>>>>>>>>>>> DictionaryType'),Field('comments','string'),
>>>>>>>>>>>>>> auth.signature)
>>>>>>>>>>>>>> db.DictionaryReferenceModel.DictionaryTypeID.requires =
>>>>>>>>>>>>>> IS_NOT_EMPTY()
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> db.define_table('Synonyms',Field('synonymName','string'),Field('wordID','reference
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> Word'),Field('comments','string'),
>>>>>>>>>>>>>> auth.signature)
>>>>>>>>>>>>>> db.Synonyms.synonymName.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.Synonyms.wordID.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.Synonyms.wordID.requires = IS_IN_DB(db, 'Word.id',
>>>>>>>>>>>>>> '%(Word)s',zero=T('choose one'))
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> db.define_table('PublicComments',Field('wordID','reference
>>>>>>>>>>>>>> Word'),Field('comments','string'),
>>>>>>>>>>>>>> auth.signature)
>>>>>>>>>>>>>> db.PublicComments.comments.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.PublicComments.wordID.requires = IS_NOT_EMPTY()
>>>>>>>>>>>>>> db.PublicComments.wordID.requires = IS_IN_DB(db, 'Word.id',
>>>>>>>>>>>>>> '%(wordName)s',zero=T('choose one'))
>>>>>>>>>>>>>>
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> On Thursday, February 21, 2013 6:10:56 PM UTC-8, Jim S wrote:
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> Can you show the model code?
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> -Jim
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> On Thursday, February 21, 2013 7:35:52 PM UTC-6, Alex Glaros
>>>>>>>>>>>>>>> wrote:
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Instead of *db.Word.dictionaryTypeID* displaying (which is
>>>>>>>>>>>>>>>> a foreign key in db.Word), I’d like a value from the foreign
>>>>>>>>>>>>>>>> table to
>>>>>>>>>>>>>>>> appear, i.e., DictionaryType. dictionaryName.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> In the example below, when user cascades down to the Word
>>>>>>>>>>>>>>>> table, it only shows db.Word.dictionaryTypeID but I’d like to
>>>>>>>>>>>>>>>> add the
>>>>>>>>>>>>>>>> corresponding DictionaryType. dictionaryName value to it.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> def search_lang():
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> grid = SQLFORM.smartgrid(db.HumanLanguage,
>>>>>>>>>>>>>>>> linked_tables=['Word','DictionaryType'], fields = [
>>>>>>>>>>>>>>>> db.HumanLanguage.id, db.HumanLanguage.languageName,
>>>>>>>>>>>>>>>> db.Word.id, db.Word.wordName, db.Word.definition,
>>>>>>>>>>>>>>>> db.DictionaryType.dictionaryName,
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> *db.Word.dictionaryTypeID*],
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> user_signature=False)
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> return dict(grid=grid)
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> id<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.id>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Wordname<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.wordName>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Definition<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.definition>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Dictionarytypeid<http://127.0.0.1:8000/tech_dictionary/default/search_lang/HumanLanguage/Word.languageID/1?keywords=&order=Word.dictionaryTypeID>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> 1 beaker glass jar 1
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Want to replace the "1" under Dictionarytypeid with value
>>>>>>>>>>>>>>>> from foreign table.
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Thanks,
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> Alex Glaros
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> --
>>>>>>>>>>>>>
>>>>>>>>>>>>> ---
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>>>>>>>>>>>>>
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