On 23 January 2013 20:27, Jason Martens <m...@jasonmartens.com> wrote:
> Hello All,
> I have a SQLFORM.grid with multiple joins that looks something like
> this:
>
> query = (db.locations.id == 10) & (db.rooms.id == db.locations.room_id) &
> (db.other.id == db.rooms.other_id)
> SQLFORM.grid(query)
>
> The problem is the edit button defaults to the other table, and I want it
> to go to the rooms table to edit the room details. How can I fix this?
>
>
> Create your own edit-button using links = ... which refers the correct
data to an edit function you have created.
When data from more than one table is displayed by a grid, you have to
specify which field you are using. Here is an example:
links = [lambda row: A(B(T('Remove')),
_href = URL(r = request, c = 'authors',
f = 'list_chosen_authors',
vars = dict(aksie= 'remove',auid=
str(row[db.akb_articles.id]))),
cid = request.cid),
lambda row: A(B(T('Add similar')),
_href = URL(r = request, c = 'authors',
f = 'list_chosen_authors',
vars = dict(aksie =
'add_similar',auid= str(row[db.akb_articles.id]))),
cid = request.cid),
lambda row: (A(B(T('Edit')), _target = "_blank",
_href = URL(r = request,
c = 'authors',
f = 'edit_author',
vars = dict(auid = str(row[
db.akb_authors.id])))))]
Regards
Johann
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