On Sun, Apr 26, 2009 at 12:14 AM, weheh <richard_gor...@verizon.net> wrote: > > Sorry, I wasn't clear. I want to do something like this: > > x=db(query0).select(db.table.ALL,orderby=something) > x.append(db(query1).select(db.table.ALL,orderby=somethingelse)) > > I get an error message about not being able to append to an SQLRow > object.
There is no .append() method, nor + operator to SQLRow objects. Maybe it can solve your problem: r1 = db(query0).select(db.table.ALL,orderby=something) r2 = db(query1).select(db.table.ALL,orderby=somethingelse) my_rows = r1.as_list() + r2.as_list() So my_rows will be a list of dicts (one dict = one row). -- Álvaro Justen Peta5 - Telecomunicações e Software Livre 21 3021-6001 / 9898-0141 http://www.peta5.com.br/ --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "web2py Web Framework" group. To post to this group, send email to web2py@googlegroups.com To unsubscribe from this group, send email to web2py+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/web2py?hl=en -~----------~----~----~----~------~----~------~--~---
