[web2py] Re: controller that don't returns a view?

[Massimo Di Pierro]

Yes, there are better ways. Instead of

def index():
     return dict(link = A('clickme',_href=URL('plus_minus')))

def plus_minus():
    do_something()
    redirect(URL('index'))

You can do

def index():
     return dict(link = A('clickme', callback=URL('plus_minus')))

def plus_minus():
    do_something()
    # no more redirect(URL('index'))

(and plus_minus will be called via ajax)
You can also do:

def index():
     return dict(link = A('clickme', 
callback=URL('plus_minus'),target='test'),
                     div = DIV(_id='test'))

def plus_minus():
    do_something()
    return "this text will go in target DIV#test"

so that you capture the response of the ajax too.



On Thursday, 6 December 2012 15:38:18 UTC-6, jonas wrote:
>
> hi
>
> I have a controller that basically inserts a number in a database. I don't 
> want it to render any view. For now I just redirect back to index.html, but 
> is there any other way to do it, i.e to have a controller that not renders 
> any views? 
>
> controller: 
>
> def plus_minus():
>
>     """ add or subtract likes """
>
>     post=db(db.blog.id==request.args(0)).select().first()
>     db.plus_minus.pm_id.default=post.id
>     db.plus_minus.insert(plus=1)
>     db.commit()
>
>     redirect(URL('index'))
>
>

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