"requests" seems common name, possible conflict ? Depending on your web2py version, check to see if the following discussions are useful
https://groups.google.com/forum/?fromgroups=#!searchin/web2py/import$20conflict/web2py/esjhf77d_jg/P0Dvc2nLur4J https://groups.google.com/forum/?fromgroups=#!searchin/web2py/import$20conflict/web2py/GY5NPJWmuMI/Nn8CNHBs1hAJ https://groups.google.com/forum/?fromgroups=#!searchin/web2py/import$20conflict/web2py/GY5NPJWmuMI/Nn8CNHBs1hAJ try changing name of your module from requests to myapprequests or some such to avoid conflict -Mandar On Thu, Nov 22, 2012 at 4:20 PM, António Ramos <ramstei...@gmail.com> wrote: > Now i have another python module "requests" that i cannot import in > web2py2.X > > why? > > > > 2012/11/19 António Ramos <ramstei...@gmail.com> > >> i moved my app to web2py2.XX and it works now! >> >> thank you >> António >> >> >> 2012/11/19 Mandar Vaze <mandarv...@gmail.com> >> >>> if pycall is under applications/myapp/modules, then try restarting web2py >>> When I created a new file under the modules folder, web2py couldn't >>> import until it was restarted >>> >>> See if it helps >>> >>> -Mandar >>> >>> >>> On Thursday, November 15, 2012 5:38:27 PM UTC+5:30, Ramos wrote: >>>> >>>> Hello >>>> i have web2py running in Ubuntu 12.04 >>>> >>>> i installed a module Pycall as root >>>> >>>> On the ubuntu console i can import pycall but if i import in a >>>> controller function i get the error >>>> >>>> def phone(a): >>>> print "calling ",a >>>> from pycall import CallFile, Call, Application >>>> call = Call('SIP/robert') >>>> action = Application('Playback', 'hello-world') >>>> c = CallFile(call, action) >>>> c.spool() >>>> return 0 >>>> >>>> *No module named pycall* >>>> >>>> >>>> Help would be apreciated >>>> >>>> Thanks >>>> António >>>> >>> -- >>> >>> >>> >>> >> >> > -- > > > > --
