Oh I am sorry, the answer was simple .... I just had to move the following line outside of the for loop pdf = FPDF() for row in rows ... instead of for row in Rows() pdf = FPDF()
On Wednesday, November 21, 2012 2:18:50 AM UTC-6, LightDot wrote: > This group is a wealth of information for other users, so when you can, > please do post what is it that you've figured out. :) > > It's highly likely someone will have the same or similar problem and > search for answers. > > Regards, > Ales > > On Wednesday, November 21, 2012 6:36:04 AM UTC+1, Paul Rykiel wrote: >> >> Nevermind ... figured it out >> On Tuesday, November 20, 2012 3:06:22 PM UTC-6, Paul Rykiel wrote: >>> >>> Greetings everyone, >>> >>> this is my code and I am having difficulity creating a "Multipage" PDF >>> to save to a directory. >>> any assistance will be welcomed. >>> >>> Regards, >>> >>> def taggen_print(): >>> rows = db(db.bike_no.id > 0).select() >>> for row in rows: >>> tag_no = row.bike_typ+str(row.id) >>> pfile = tag_no+'_p.pdf' >>> pdf = FPDF() >>> pdf.add_page() >>> pdf.set_font('Arial', 'B', 14) >>> pdf.cell(40,10,tag_no) >>> pdf.output(name=request.folder + '/static/temp.pdf') >>> response.headers['Content-Disposition']='attachment.filename =' + >>> pfile >>> response.headers['Content-Type']='application/pdf' >>> return response.stream(open(request.folder+'/static/temp.pdf', >>> 'rb'),chunk_size=4096) >>> # pdf.output(pfile, 'F') >>> redirect(URL("index")) >>> >>> right now it only saves the PDF for the last record... I need it to >>> create a page for each record and save it in PDF format in the directory >>> >> --