web2py users,
I'm running apache2 with mod_wsgi. I ScriptAlias the wsgihandler.py
not as the root of the server but with it's own directory. From my
vhost file:
WSGIScriptAlias /appName /opt/web2py-1.49/wsgihandler.py
<Directory "/opt/web2py-1.49">
Order allow,deny
Allow from all
</Directory>
To access the application, I need to do http://servername.com/appName/appName.
What's the best way to route off that second appName. I tried
"renaming" my application as init in the applications folder but
web2py then cuts off the first appName and apache fails to use the
wsgi server.
Thanks,
Mark
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"web2py Web Framework" group.
To post to this group, send email to web2py@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/web2py?hl=en
-~----------~----~----~----~------~----~------~--~---
