Here is some mail from people who can't understand what I am talking about, and my reply
Pioneering the Applications of Interphasal Resonances http://tech.groups.yahoo.com/group/teslafy/ --- On Sat, 1/14/12, Harvey Norris <[email protected]> wrote: From: Harvey Norris <[email protected]> Subject: Re: Variations such as cosC = ( a²+ b²− c² ) / 2ab are directly suited for the SSS case. To: "Karl Bender" <[email protected]> Date: Saturday, January 14, 2012, 2:26 PM Pioneering the Applications of Interphasal Resonances http://tech.groups.yahoo.com/group/teslafy/ --- On Fri, 1/13/12, Karl Bender <[email protected]> wrote: From: Karl Bender <[email protected]> Subject: Variations such as cosC = ( a²+ b²− c² ) / 2ab are directly suited for the SSS case. To: "Harvey Norris" <[email protected]> Cc: [email protected] Date: Friday, January 13, 2012, 5:04 PM “SSS” means “Side, Side, Side”. The Law of Cosines could be applied in the SSS case, in which all three sides of the triangle are given and want to find the missing angles. Variations such as cosC = ( a²+ b²− c² ) / 2ab are directly suited for the SSS case. Example of SSS: Given: a = 4 in. , b = 5 in. , c = 7 in. Use The Law of Cosines first to find one of the angles. In your final answers, round off angles to the nearest tenth of a degree. Solution: A model triangle may not be as helpful here This Works!!!!!! http://lawofcosines.com/high-school-trigonometry-law-of-cosines-to-solve-sss-case/ You give me a = 3, b = 4, c = 5 ( a² + b² − c² ) / 2ab ( 3² + 4² − 5² ) / 2(3)(4) ( 9 + 16 − 25 ) / 2(12) ( 25 − 25 ) / 2(12) ( 0 ) / 24 ?????? Go Back To School. Does not work with right triangles. This Does Not Work!!!!!! I forgot to use the reply icon, so I will explain this one more time. The above cited equations do not show all the work involved, they assume you are not an idiot that when he gets an answer that is zero, he throws up his hands into the air, saying this don't work for zero! Let me later give a simple example of an equilateral triangle of 1 unit sides. We know that all three inner angles are 60 degrees. But first I should go back to school where they gave me a best answer here; When do I use radian mode?http://answers.yahoo.com/question/index;_ylt=AnQyWpapkA7c1DM55yRIzCLty6IX;_ylv=3?qid=20090119145608AAZlv3o For Trigonometric functions a degree measurement as the "x" part of f(x) or Y = how x is manipulated; for the trigonometric functions the x manipulation part is expressed in radians where they are 2 pi radians, or radii in the circumference of a circle. 90 degrees is one quarter of that total, or 2pi/4. To find the answer to sin of 90 degrees which is one Y unit coordinate of the y component of the vector expressed in degrees, you must first convert the 90 degrees into radians by multiplying by 2pi radians/360 degrees, yielding sin(2pi/4)= 1 Here we see that the sin(of a certain number of radians)= 1 Guess what? (the hypothetical no. made as law of cos calculation IS that certain amount of radians to be used for the cos function which then gives an answer; which of course another set of calculations are then necessary to convert the answer back into degrees. Now a right triangle has zero as the numerator of the fraction, making the entire law of cos answer also zero, but we know the answer that will be derived is 90 degrees because we have used the equation to find the angle opposite to the hypotenuse. So we ask the question; how many radians are necessary so that the cosine of that amount of radians will equal zero. This is done on the calculator NOT by using the cos function, but by using the inverse cos, cos^-1, or sec function. The cos function is x/radius or x/r while the secant function is the inverse or r/x. So I go to my calculator and punch in cos^-1(0)= 1.5707,(this is actually the same no shown above as 2pi/4 where the radian conversion was 90 degrees) I now do the radian conversion, since the answer got was expressed in radians. There are 360 degrees/2pi radians. 1.5707*(360/6.28)=90.04. If I use the actual pi no on the calculator I get 90. Now let us do the equilateral triangle; cos (x)=[(1^2+1^2-1^2)/(2*1*1)]=1/2 cos^-1(1/2)=1.047 radians =1.047(360/2pi)= 60, answer now converted to degrees. Notice that in the example you supplied when the third angle was found, rather then to go through the calculations, they merely subtracted the previous totals, because they knew that the sum of the angles inside a triangle was 180 degrees. Now the dispute I still further have is that you seem to maintain that the law of cosines cannot be applied to find the acting phase angles of a three phase process involving mutual induction between the phases. Just like the zero problem, you may not fathom how if three phase goes in, then the output will also be that same three phase, perhaps disguised in a way. So this is what I did to show how a vector movement in space described by the law of cosines will "disguise" the phase so that appears as a different phase angle made by the tensor translation. In effect the topology change PREDICTS what the translation will look like! What I did was to take your advise and drew the vectors out on a piece of paper to scale. Each of the appropriate resonant voltage rises was given as the magnitude of the vector, and the phase angle between them determined by the law of cos; whereby the voltage measured BETWEEN each resonant voltage, referred to as the interphasal voltage, that quantity was used as the hypotenus to find its opposite angle created when the three magnitudes are plotted as a 2d triangle. Thus in terms of the law; The sum of the phasal resonant squared voltage rises minus the square of the interphasal voltage between them/ All divided by the twice the multiplication of the phasal voltages This quantity has the angle between the phases determined by taking the cos^-1 function of that no and converting the answer into degrees Now surprisingly when the three vectors were plotted they looked about what three phase looks like. The voltage magnitudes were 8, 7, 7.2 volts on the three phases in order. Between the phases 1 and 2 having 8 and 7 volts we find 12.9 volts, where according to law of cos is 118.5 degrees. So I took out a protactor and drew out the vectors at that phase angle. Now the voltages on phases 2&3 were 7 and 7.2, with 11.3 volts between them. This comes out to 105.5 degrees. The three vectors look like three phase, and when we employ dual channel scopings of all the three top magnetic fields they appear as ~120 phase angles. Remember then how the teacher ASSUMED that he could employ subtraction to determine the remaining result? After all there is 360 degrees in a circle of time, or so we suppose, and we have used up 224 of them, which should leave 136 degrees over. What the pancake 666 machine does is to contract time where the topology change from the tensor showing the 2d to 3d transformation itself PREDICTS what the new phase angles will be! This is seen by the following conclusive argument. As mentioned phases 3 and 1 have 7.2 volts and 8 volts respectively. BUT the voltage measured between them is only 2.34 volts. THIS SINGLE VOLTAGE MEASUREMENT IS THE MOST SIGNIFICANT MEASUREMENT EVER MADE PAST THE ECLIPSE OF THE SUN TO VERIFY RELATIVITY. That measurement shows that a machine to manipulate time to create a "localized space time curvature" are if fact possible. I glossed over this fact for months, not knowing its significance, and just concluding, "oh well those two are closely in phase and of little value for load placement, since a very small voltage is between them". Had I not drawn out the vectors to scale on a piece of paper as you may have suggested, I would have never discovered this stupendous thing. When we apply the law of cos for the remaining (1-3) phase angle we find 16.7 degrees. We can keep going around the circle and plot the next vector, which I did. But heres where the paradox comes in. This same information also tells us that another vector exists 16.7 degrees away from phase 1's vector, beside the one just made that sits next to phase 3's vector, and the angle between those vectors "looks" like about 1/3 of the circle. The vector cannot be in two places at once. So what is demanded Is that we use that "famous" voltage reading to finish constructing the vector assembly ACCORDING TO THE LAW OF COS! This demands that the distance between the ends of phase 1 and 3 vectors must be decreased to 2.34 units according to the scale diagram. This is accomplished by cutting out 1/3 of the circle as a pie shaped piece representing the missing time, and folding the diagram into a cone! This is the actual topological change made as the transformation from 2d to 3d to satisfy the vector requirements made by the law of cosines. Let us analyze how the transformation predicts the new phase angles. When we drew out the last small vector phase angle extending past phase three, we may measure the distance between the ends of the vector on the 2d diagram, and use that information to form the angle. However in the process of the transformation from flat 2d to curved 2d, the distance between the points in time of the former 16.7 degree phase angle will become TRANSFORMED into a closer distance for the simple reason that the measurement itself is made across a curved space time 2d vector diagram, and a shorter distance actually exists between those points in actual space. It is this deviance of values between the actual distance and the curved distance that determines the amount of phase angle change made in the transformation. After this folded cone is made and viewed from the apex the phases 1 and 2 that were formerly 118.5 degrees separated in time on the 2d diagram, now they directly appear to be at 180 degrees! If this topology is correct, it should be shown somewhere as the time separation of magnetic fields amongst the six ones available from the poles of the 666 machine. And sure enough two of those fields can be found. So in essence this prooves that the law of cosines can be used to calculate the phase angle changes made in the transformation from one system to another, and incredibly enough here that law is applied in three dimensions, not merely two. Sincerely HDN
