Hi David
how do you consider *facts* these data ? All we have in our hands are
Rossi's  claims.

2011/11/6 David Roberson <[email protected]>

>  I would like to have access to the known facts associated with the
> latest test of the 1 MW ECAT system.  Is it possible for us as a group to
> keep a list of what we know must be true about the test and other facts
> that influence the measured performance?  I am including a beginning list
> that should be reviewed for accuracy and appended to by vortex members.  Thank
> you.
> 1). The ECATs were preloaded with water prior to beginning the test.
> a). A reasonable estimate of the water held within the 107 ECATs is 107
> units x 30 liters/unit = 3210 liters.
> b). The water within the 107 ECATs is replaced in approximately 3210
> liters / 675.6 liters/hour = 4.75 hours.
> 2). There is no pump within the output path between the ECAT’s and the
> large water storage tank.
> a). This configuration absolutely demands that the output vapor must be
> greater than atmospheric pressure. This is necessary to push the water out
> of the dissipaters.
> b). This pressure can be estimated by someone who is skilled in the
> calculation of liquid and vapor flow through pipes and dissipaters.
> 3). The average input water flow rate for the ECAT’s was 675.6 liters/hour.
> a). The output flow rate is 675.6 liters/hour / 3600 seconds/hour * 1000
> grams/liter = 187.667 grams/second.  Using this value and information
> from NIST leads to the following conclusion.
>             b).  105 C is the average temperature output of the system,
> and 18 C average input.
> c). If only liquid water is ejected by the ECATs, the minimum system power
> output is 187.667 grams/second * (440.27 joules/gram liquid at 105 C –
> 75.544 joules/gram liquid at 18 C) = 68.45 Kilowatts.
> d). If vapor is the only output then the maximum system power output is
> 187.667 grams/second * (2683.4 joules/gram vapor at 105 C – 75.544
> joules/gram liquid at 18 C) = 489.4 Kilowatts.
> e). The true power output of the system must lie between these two values.
> 4). The customer had an engineer named Domenico Fioravanti and helpers to
> verify operation of the system.
> Dave
>

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