I agree the gas flow out the end of the black hose seems to be visible right at the end -- whereas steam would be invisible for a short distance.
Trained as a dishwasher since age 10, 80 miles E of Houston, Texas, I am sure that hot water gives off mist in low altitude, warm, humid climates. Rossi seems to be saying that "cool" steam is slightly visible as a mist, while "hot" steam is invisible! All steam is invisible, by definition. Rossi seems to me to be natural, relaxed, matter of fact, genuine. Isn't it possible for the pump to fill the reactor up totally with water, which would then overflow and exit as water just below boiling, or water exactly at boiling, mixed with variable amounts of steam? Would any bubbling at the outlet of the reactor be audible? How noisy is the background? Since about 1 m of the hose lies on the floor, before rising about1.5 m to pass through a hole in the wall, wouldn't that part of the hose on the floor fill up completely with water, with a flow of 7 kg/hour? How much pressure results from the 1.5 m rise in the hole? Also the hose on the floor, if full to 1.5 m, would be equally full on both arms of its "U" bend... If so, then would that ensure that all steam is condensed while passing through a full "U" bend? How much output heat is there if very little of the water is boiled within the reactor? My guess is that the Rossi team actually don't have a clue about what is happening between the device outlet and the far end of the hose.
