The extremely high cost of enrichment has to rule this possibility out. 
  ----- Original Message ----- 
  From: Peter Gluck 
  To: [email protected] 
  Sent: Saturday, May 07, 2011 1:57 AM
  Subject: Re: [Vo]:Explainig Rossi.


  Can you evaluate the costs of enrichment?


  On Sat, May 7, 2011 at 9:47 AM, Axil Axil <[email protected]> wrote:

    Explaining Rossi.



    Rossi said: “We think that all the Ni participates to the reactions, even 
if some isotopes should be more efficient.” “Only Ni 62 and Ni64 react.”



    Rossi enriches his nickel in Ni62 and Ni64. Why? Through experimentation, 
Rossi found these isotopes performed best. But what is the theory behind this 
result?



    Nickel-62 is an isotope of nickel having 28 protons and 34 neutrons. It is 
a stable isotope, with the highest binding energy per nucleon of any known 
nuclide (8.7945 MeV). The high binding energy of nickel isotopes in general 
makes nickel an "end product" of many nuclear reactions (including neutron 
capture reactions) throughout the universe and accounts for the high relative 
abundance of nickel and nickel-60 (the second-most, with the other stable 
isotopes (nickel-61, nickel-62, and nickel-64) being quite rare).



    Nickel is the least likely element to participate in a fusion reaction. 



    If atomic holes are the place where the Rossi reaction occurs, Rossi wants 
a very strong and stable support structure that can provide a three dimensional 
quantum box that can produce the reaction. 



    Under the assumption that only hydrogen reacts in the quantum box and that 
many hydrogen atoms are fused in the Rossi reaction; the packing of all those 
hydrogen atoms into the lattice defects of nickel is a stressful process. If 
this nickel built Heisenberg box were to fail or fail apart during the packing 
of hydrogen, then the reaction will fail. 



    Nickel is the most stable element because its binding energy is maximized 
among the elements. The nickel isotopes that are the most stable are Ni62 and 
Ni64. Rossi enriches his nickel in these most stable and stout isotopes because 
they can best support the atomic defects he uses to produce atomic events 
without blowing the lattice defects apart during the stresses of the atomic 
reactions and were nickel garbage would poison the pure hydrogen  reaction. 



    Elements on either side of nickel will perform best because of their very 
high binding energies.






  -- 
  Dr. Peter Gluck
  Cluj, Romania
  http://egooutpeters.blogspot.com

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