Rossi says that many elements beside nickel will work. The patent says that Copper will work also. The reason: it is the atomic holes that produce the reaction in a transition metal. It is these holes that are the active nuclear sites. The support is the oxide of that metal whatever it is. This oxide is a dielectric and provides support for the pure metal surface cover. The hydrogen generates the atomic holes by erosion at startup.
On Fri, May 6, 2011 at 4:46 PM, Jones Beene <[email protected]> wrote: > There is no mistake in your numbers, so far …. but …. > > > > As you may know, I think Rossi is deliberately seeding the internet > discussions with packets of disinformation, since he does not want > replication. I think that you and many others on vortex trust him too much, > and I do not. > > > > Therefore, I can only go on what I am seeing and hearing first hand. From > the projects which I have been involved with recently, and admittedly we > have not come close to Rossi’s hero numbers, the minimum amount of nickel > would needed to get to kilowatts is near where you say – 100 grams - more or > less. I think it is more than that. This would need to be embedded in a > dielectric. My feeling is the dielectric is the same as Arata – zirconia. > > > > An associate has analyzed the lines on the spectrographs in the Patent > Application has found that the only 100% match for all the lines is zirconia > and one other element which I cannot disclose now. Of course nickel is > nearly 100% but this indicates that there is at least twice as much > zirconium as nickel, so zirconia is at least part of the support. > > > > The fact that Focardi mentions Arata’s extreme contribution make me think > that anyone contemplating replication should pay attention to him (and > Takahashi/Kitamura). > > > > Jones > > > > *From:* Axil Axil > > > > > > nickel has a density of 9grams /cc > > > > 100 grams of nickel / (9 grams /cc) = 11 cc > > > > 11/1000 = 1% > > > > where did I go wrong? > > >
