On Wed, Jan 12, 2011 at 11:38 PM, David Jonsson < [email protected]> wrote:
> I have derived an effect which differs from Newton/Kepler orbits but with > the wrong sign apparently increasing the problem even more. > > I would be glad if someone could check the calculations before I take them > further. It would also be nice to calculate on some real example. > > > http://djk.se/Dark%20matter%20problem%20approached%20with%20classical%20physics,%20local%20rotation%20increases%20the%20centrifugal%20force%20away%20from%20the%20galaxy%20core.pdf > > How big is the anomalous acceleration at our solar system? > OK, the solar system is an example where the effect is very small and practically negligible. I have been looking for binary stars where the effect might be noticeable and it seems like HM Cancri is such a case http://en.wikipedia.org/wiki/RX_J0806.3%2B1527 Those white dwarfs spin around each other at 500 km/s. I give all the details for the calculation in case anyone wants to check them. With the help of this nice tool http://fuse.pha.jhu.edu/cgi-bin/eqtogal_tool i could calculate the galactic coordinates based on the coordinates in Wikipedia, which gave me Epoch J2000.00 coordinates: 08 06 23.20 + 15 27 30.2 = Galactic coordinates: LII=206.9253 BII= 23.3960 Leading to this distance in lightyears from the galaxy core *((((cos(((207.3669 - 180) / 360) * 2 * pi) * 16000) + 26000)^2) + ((sin(((207.3669 - 180) / 360) * 2 * pi) * 16000)^2) + ((sin((23.9625 / 360) * 2 * pi) * 16000)^2))^0.5 = 41389.7368 light years **= 12.689869 kpc *Which according to this graph http://en.wikipedia.org/wiki/File:Rotation_curve_(Milky_Way).JPG has about the same orbital speed around the galaxy of 220 km/s as our solar system The equation I derived on the top link says a = (vs^2 + vp^2/2)/r which means centrifugal acceleration depends on both the stars' speed in the orbit around the galactic core vs and the spinning speed around its binary vp. Classical acceleration ac = vs^2/r compared to a is a/ac=(vs^2 + vp^2/2)/r/(vs^2/r) = (vs^2 + vp^2/2)/r/(vs^2/r) = (220^2 + 500^2/2)/220^2 = 3.6 So in this case the gravitational pull has to be 3.6 times higher than even the dark matter addition. I think I add this to the document as a relevant example. What would happen in the case of lack of that strong gravity? David
