In reply to Roarty, Francis X's message of Thu, 27 May 2010 11:09:24 -0400:
Hi,
[snip]
>I finally got a chance to finish the W-L article and subsequent series of
>neutron absorptions and beta decays following the ULM neutron formation. I
>would agree with Eds assessment that a rose by any other name is still a
>rose. If a neutron absorption is normally considered fusion then this
>Should still be considered fusion even if the wave length is longer and the
>fusion is colder.
>Regards
>Fran
>
>
>Li-6 + n -> Li-7 + n -> Li-8 -> Be-8 + e? + {neutron absorption, then
>betadecay} (4)
As I pointed out to Larsen in private email, this reaction is silly. Why start
with Li-6 when you can start with Li-7 which is far more abundant in nature
anyway?
>
>Be-8 -> He-4 + He-4 {perfectly symmetric, green fission of a beryllium-8
>nucleus} (5)
>
>He-4 + n -> He-5 + n -> He-6 {neutron absorption, making neutron-rich
>helium} (6)
This is also silly. He-5 decays to He-4 and a neutron with a half life on the
order of femtoseconds, so the chance of going on with a second neutron to form
He-6 is miniscule.
>
>He-6 -> Li-6 + e? + {final beta decay of helium- 6 that regenerates
>lithium-6} (7)
>
>The above series of nuclear reactions comprise a reaction cycle in that
>lithium-6 is regenerated as the final reaction product [2]. Lattice has also
>uncovered other LENR reaction cycles that release varying amounts of energy.
If you really want to make Li-6, the simpler reaction is:-
He-4 + D => Li-6 + 1.47 MeV, but oops, no neutrons involved. ;)
Regards,
Robin van Spaandonk
http://rvanspaa.freehostia.com/Project.html
