-----Original Message----- From: Abd ul-Rahman Lomax > Thus, like most evaporations, the escape of deuterium from the lattice must cool it.
No. The inversion temperature of hydrogen is low, and there is no cooling on expansion from the Joule-Thomson effect - as with an ideal gas. In fact it heats. That is the very crux of the cigarette lighter hypothesis, which apparently you missed :) If not for the inversion temperature heating effect, the Pd in the lighter would never release much gas to begin with, and no cigarettes would get lit. Note this was an actual lighter design at one time and addicts do not like to get fooled. When air initially at a moderate temperature is expanded through a valve, its temperature decrease because it starts out below the inversion temperature of the constituent gases, and the expansion will cause a temperature reduction as the result of the Joule-Thomson effect. Any gas expanded at constant enthalpy will experience a temperature decrease ONLY if is below the inversion temperature, however, and if above it will usually experience a temperature increase. The inversion temperature of hydrogen is lower than ambient as the table below demonstrates: Gas Inversion Temp Deg K Helium 51 Hydrogen (H2) 205 Neon 242 Nitrogen (N2) 621 Argon 723 Krypton 727 Oxygen (O2) 893 > No. Arata does not show excess heat with hydrogen. Maybe it is Kitamura then, but one of them shows substantial heat from hydrogen nanopowder too, with no added input other than the trigger heating - but more from deuterium. Citation to follow (when I get a spare moment) Jones
