Jed Rothwell wrote: > I would appreciate it if someone could check my arithmetic. > > Roulette data from: > > http://lenr-canr.org/acrobat/RouletteTresultsofi.pdf > > UO2 data from ANS and the source Terry found. > > > > 1 pellet of UO2 fuel weighs 7 g and produces as much as 3.5 bbl of oil. > 3.5 bbl = 147 gallons. > As 131 MJ/gallon that's 19,257 MJ/pellet or 2,751 MJ/g UO2 > > 1 g of oil produces 0.042 MJ > > Roulette used cylindrical cathodes 100 x 2 mm = 0.314 cm3 > Density of Pd = 12.023 g/cm3 > So that's 3.77 g per cathode, about half of the 7 g fuel pellet > > Roulette reported the longest run of 158 days (5 months), with 294 MJ > output. That's 78 MJ/g. > That is 35 times less than UO2. It is 1,857 times more than oil. > > To put it another way, if Roulette had left this cathode running for 15 > years, instead of 5 months, it would have produced 10,385 MJ, or about > as much as 3.77 g of UO2 (a half-pellet). The average operating cycle > for UO2 (the EFPD) is about 400 days, I think.
The arithmetic seems fine but I don't really understand why you're computing this. The palladium isn't the fuel, it's just a catalyst, and the worst that happens to the cathode is its surface get munged. If "reprocessing" is needed after a while due to wear and tear on the cathode it should be pretty straightforward, with essentially 100% of the palladium recoverable.
