The prior comment from Robin actually reminds me of a recent thread here about a possible "backdoor" way to get the Holmlid effect. This alternative route would not violate conservation of baryon number, in fact.
The hypothetical route would involve nuclear charge flipping. Here is the thread. https://www.mail-archive.com/[email protected]/msg117275.html It could happen without the baryon violation using deuterons and anti-deuterons as well as protons etc. Jones Beene wrote: Robin - No apparent violation there since the baryon number on both sides of the reaction is 0 p+ + p– → γ (gamma ray) + γ (gamma ray) IOW when the proton and antiproton come into contact, they annihilate into two high-energy photons. [email protected] wrote: Perhaps I misunderstand conservation of Baryon number, but isn't proton : anti-proton annihilation an obvious violation?
