In reply to [email protected]'s message of Mon, 29 Aug 2016 15:59:40 +1000: Hi,
BTW, after distribution of reaction energy over both the new Ni59 nucleus and the proton, the proton ends up with 6.66 MeV which rounds nicely to 6.7 MeV. [snip] >If the measured energy of the proton is 6.7 MeV, then a more likely reaction >is: > >D + 58Ni => 59Ni + 1H + 6.775 MeV > >with the D being a minor contaminant in ordinary Hydrogen. 58Ni makes up the >majority of all Ni atoms. The 59Ni is only very mildly radioactive (ec => >neutrino), but produces no significant gamma rays. The proton would carry most >of the energy of the initial reaction, which it would lose primarily through >ionizing other atoms, resulting mostly in heat. However it would also produce >some secondary gammas during a direct hit on a nearby nucleus. [snip] Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
