Is the vacuum just another name for the Dirac Sea? If so it would seem that a strong magnetic field may direct the charged W bosons away from Axil’s wormhole, making it harder for the charged W’s to appear in the muon’s zone of space. The Z boson being neutral may not be so effected and still be able to appear as scheduled, based on its location relative to the wormhole.
One interesting muon feature, based on theory and observations is that it has a property called hypercharge. It is a combination of charge and isospin (not the same as inintrinsic spin, but similar, I think). The value is a scalar quantity as best I can tell, like quantum numbers in a wave function. The density of the weak force bosons in the Dirac Sea—vacuum—may be responsible for the observed mean half-life of the muons. This may be a key as to how coherent systems juggle charge and spin, as well as their communication with the vacuum. Bob Cook From: Roarty, Francis X Sent: Friday, August 14, 2015 6:38 AM . : [email protected] Subject: Re: [Vo]:Re: Muons, SPP, DDL & RPF Axil, much better said than my relativistic warp via confinement but we are on the same page. IMHO even catalytic action is a weak form of this mechanism. I think catalysis is just the rate of change in low level dilation due to the tapestry of geometry in active regions. I think LENR is bootstrapped from an intense form of catalysis where the dilation factors reach relativistic levels and because they are based on an inverse square cube [Casimir or other London form] they trump the gravitational square law causing breaches in the isotropy that LENR exploits. Regards Fran From: Axil Axil [mailto:[email protected]] Sent: Thursday, August 13, 2015 10:05 PM To: vortex-l Subject: EXTERNAL: Re: [Vo]:Re: Muons, SPP, DDL & RPF The muon decays when a W- appears from the vacuum. This appearance is timed by the probability of the decay of the muon. But if the vacuum is energized so that it has an excess of positive vacuum energy. then the W- will not appear on time, it will be delayed.Excess vacuum energy slows down time. A excess of positive vacuum energy appears if a corresponding zone of negative vacuum energy is present. That zone of negative vacuum energy exists inside the SPP. Negative vacuum energy speeds up time a lot. This acceleration of time is why radioactive isotopes produced by fusion in LENR decay almost instantaneously. That is because the ash from a fusion event is entangled with the inside of the SPP in which all the energy of the fusion event is delivered. On Thu, Aug 13, 2015 at 8:31 PM, Bob Cook <[email protected]> wrote: Jones, Eric and Axil-- I have been trying to understand the mechanism of muon decay, but am still in the dark. The muon is said to be a lepton—a primary particle not made of any constitutents—yet it frequently decays into three particles, including neutrinos that are normally not observed but inferred. The standard words explain that muon decays by a weak force interaction, however an interaction with what?—it’s not said. And what happens to a muon, if it is in empty space with nothing with which to interact? It seems W+, W- and Z^0 (0 charge) bosons, the carriers of the weak force, are involved, but do they appear at random from the vacuum to disrupt a free muon, causing it to decay? And why is the half life of a free muon so short? If a massive boson mediates the decay, what happens to the boson? Does it disappear back to the vacuum? The bosons are said to be very short lived--10^-18 sec. Bob Cook . From: Axil Axil Sent: Thursday, August 13, 2015 11:09 AM To: vortex-l Subject: Re: [Vo]:Re: Muons, SPP, DDL & RPF There are indications that Muons are extended in there lifetimes by Rysberg matter. The muons are produced for hours and days after the Rydberg matter is exposed to light. As referenced from the HolMlid paper as follows: " The sources give a slowly decaying muon signal for several hours and days after being used for producing H(0). They can be triggered to increase the muon production by laser irradiation inside the chambers or sometimes even by turning on the fluorescent lamps in the laboratory for a short time." But in the experiment, the ability to extend the lifetime of muons is not open ended in time. There is a reduction of muon detection over time. If the ability for Rydberg matter to extend the lifetime of muons was open ended, the count of detected muons would reach a stable condition since cosmic muons arrive at a relitivly constant rate. . I believe that this ability to extend Muon lifetimes is rooted in the coherent superconductive nature of Rydberg matter. Furthermore, the mean energy of cosmic muons reaching sea level is about 4 GeV. Muons, This energy level is higher than the levels seen by Holmlid in his experiment. This implies that the muions seen in the experiment were produced locally by Rydberg matter. On Thu, Aug 13, 2015 at 10:38 AM, Jones Beene <[email protected]> wrote: To paraphrase what Bob has said and cited, there is little possibility of a spin problem, when it is proposed that the SPP can extend the lifetime of muons (as opposed to creating them from nothing). I think that we all agree that “extending the lifetime” of a catalytic particle like the muon, where there is already a flux coming from the natural source – is functionally identical to “making” them anew. In either case, a higher population accumulates. Since any interaction with protons would happen within the geometry of the strong force, it is subject to QCD, and consequently giga-eV are in play, so the source of energy is no mystery. Proton mass is not quantized. In the end, until Holmlid’s experiment is better explained as something other than detection of muons in a situation where SPP are acting on dense hydrogen, he should be given benefit of the doubt. No? This would mean that a valid, if not intuitive, explanation for the thermal anomaly in the glow-type reactor (incandescent reactor) involves muons interacting catalytically with protons, where the muons appear to be either created from the reaction, or else do not decay as normal, following the reaction. This scenario will include a thermal anomaly which does not involved gamma radiation. This M.O. leaves open three possibilities for explaining the thermal anomaly – one which is covered by Storms. He suggests that protons fuse to deuterium, despite the spin problem, and lack of evidence in the ash. Another possibility is that SPP formation is inherently energetic – but this is unlikely since SPP are seen in optoelectronics with no energy gain. My suggestion is simpler and based on the solar model. It suggests that the catalyzed fusion reaction happens but is instantly reversible, due to Pauli exclusion. Excess energy derives from conversion of a portion of proton mass to energy via QCD during the brief time when the diproton exists as a helium-2 nucleus, before reverting to two protons and a renewed muon. Until there is evidence of deuterium in the ash we have an ongoing debate in which the physical evidence favors one argument over the other. From: Bob Cook Eric-- Note my comment to Jones before I read your questions. Bob From: Eric Walker Jones Beene wrote: D+D + muon → helium-4 + muon (instead of gamma) … where the fist muon can be a cosmic muon which can catalyze a reaction and then be rejuvenated, renewed or replaced by the same fusion reaction that it catalyzes. The muon is a “heavy electron” with a short life, but now we can surmise that it can have its lifetime greatly extended as part of the catalysis. The probability for this to occur is larger than zero, but how large? … “Maybe it’s pretty high” says Byrnes. Can it explain the lack of gamma, as well? Probably. But now, as we are learning – this rebirth effect will be more robust with SPP and fractional hydrogen. A muon could possibly carry away as kinetic energy the energy that would otherwise go to a gamma. But if we're talking about a single muon, how do you propose that the spin of the missing photon is conserved? Eric
