Just do ":help min()", it will tell you:
min({expr}) Return the minimum value of all items in {expr}.
{expr} can be a |List| or a |Dictionary|.
So the simplest solution seems to be:
trunc(min([3, float2nr(1+log(1+line('$'))/log(10))]))
On Sat, 2 Jan 2021 at 22:49, L A Walsh <[email protected]> wrote:
> I have the expression:
>
> trunc(1+log(1+line('$'))/log(10))
>
> to give me the width of the number columns when numbering is
> on. Seems that it is reserving a minimum of 3 columns, so I tried
> using the 'min' function:
>
> trunc(min(3,1+log(1+line('$'))/log(10)))
>
> but I get E118: Too many arguments for function: min.
>
> huh? so how does one use 'min' to determine the lowest of 2 or
> more numbers, or why doesn't the above work? :-(
>
>
> *sigh*,
> tnx
>
>
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