Fahmi, when i access to http://localhost:8080/myapp/maiservlet tomcat display this error: java.lang.ClassNotFoundException: servlet.maiservlet
I have Tomcat 7.0.8. 2011/3/31 Fahmi Hachicha <fahmi.hachi...@gmail.com> > Hello, > > You can map the sevlet in this manner in your web.xml > > <servlet> > <servlet-name>maiservlet</servlet-name> > <servlet-class>servlet.maiservlet</servlet-class> > </servlet> > > > <servlet-mapping> > <servlet-name>maiservlet</servlet-name> > <url-pattern>/maiservlet</url-pattern> > </servlet-mapping> > > Good lack > Fahmi > > 2011/3/31 Justin Randall <ran...@hotmail.com> > > > Read up on web.xml and using Serlvet mappings to define paths that map to > > the Servlet class itself. > > > > It looks like you're currently using direct servlet invocation. > > > > ------Original Message------ > > From: Jonatan Aguirre Kobayashi > > To: users@tomcat.apache.org > > ReplyTo: Tomcat Users List > > Subject: Customize URL access > > Sent: Mar 31, 2011 09:17 > > > > Hello, a have a application and the url is for example > > http://localhost:8080/myapp/servlet/maiservlet. > > How i do to access to my application with this url: > > http://localhost:8080/myapp/maiservlet (without servlet reference) > > > > > > PD: Sorry , my english is not good. > > > > > > > > Sent from my BlackBerry device > > > > --------------------------------------------------------------------- > > To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org > > For additional commands, e-mail: users-h...@tomcat.apache.org > > > > >
