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Bill,

On 4/22/2010 2:37 AM, Bill Barker wrote:
>> It's pretty inaccessible for novice Java programmers, but you could use
>> the "proxy" API which is [just] about the coolest thing available in
>> Java IMO.
>
> If it does a forward or include done the line, this won't work with any
> remotely recent version of Tomcat.  These versions enforce the spec
> requirement that the Request has to be a subclass of HttpServletWrapper
> wrapping the original request, or the original request.

How does Tomcat enforce that? HttpServletRequestWrapper doesn't expose
the underlying request.

I must admit that I didn't try it. I should.

- -chris
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