tiffany.d...@inovis.com wrote:
I installed Tomcat 6.0.20 on 64bit Window2003. I installed 64 bit tomcat
service (64 bit tomcat6.exe and 64bit tomcat6w.exe).
I set variable name of JRE_HOME to the path of my 64bit JRE 6.0.
Where did you set that variable ?
When running Tomcat as a service under Windows, using the tomcat6.exe
wrapper, the environment parameters, path to JVM etc.. have to be set
using the tomcat6w.exe program. This is a GUI (graphical) program,
which you start on the console just by double-clicking on it.
A bit of explanation, which is available somewhere else in the docs but
I don't remember where :
Tomcat is a Java program.
It is run by a JVM.
The JVM is thus the real program which runs under Windows.
But the JVM, by itself, does not react very well like a Windows Service
is expected to.
So someone invented a "wrapper program", which gets installed and acts
as the Windows Service; and this program runs the JVM.
That wrapper program is tomcat6.exe.
This wrapper program looks for some of its parameters, in the Windows
Registry.
The tomcat6w.exe program is a GUI programs that helps setting these
Registry parameters in the right place.
So start tomcat6w.exe, and navigate through the tabs, to see where it
thinks it should find the JVM. Your problem is probably there.
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