Hi,
Thanks for the help. Can you tell me how to compile these .java files into classes in Eclipse(3.4)? All these java files are under "command" package. Thanks Sam > ----- Original Message ----- > From: Tandel, Aswin > Sent: 26/08/08 02:23 am > To: Tomcat Users List > Subject: RE: how to reference a class to the current src directory. > > Hi, > > For the classes in the same directory it is not required to give class > path reference. > > Chances are that DatabaseCommand is not compiled. > Check if you have the class file in bin directory. > > If not then clean the project and build again > > > Thanks and Regards, > Ashwin Tandel > Email - [EMAIL PROTECTED] > > -----Original Message----- > From: sam wun [mailto:[EMAIL PROTECTED] > Sent: Monday, August 25, 2008 12:04 PM > To: Tomcat Users List > Subject: how to reference a class to the current src directory. > > Hi there, > > I have created a Web project using Eclipse 3.4. However, it can't resolve > the class reference to the current directory. > Here is the project layout and description of the problem: > > >DBTest > >src > > command > CommandExecutor.java > ... > ... > DatabaseCommand.java > ... > > > Double-clicks on the file CommandExecutor.java, it display the following > content: > > package command; > > import java.sql.Connection; > import java.sql.SQLException; > import javax.sql.DataSource; > import javax.naming.InitialContext; > import javax.naming.Context; > import javax.naming.NamingException; > > /** > * Gets and caches data sources, gets connections > * Implements Singleton pattern > */ > > public class CommandExecutor { > > private static CommandExecutor myOnlyInstance = null; > private DataSource ds = null; > > // accessor method for the singleton > public static CommandExecutor getInstance() throws NamingException > { > if (myOnlyInstance == null) { > myOnlyInstance = new CommandExecutor(); > } > return myOnlyInstance; > } > > // Constructor for the singleton > private CommandExecutor() throws NamingException { > getDataSource(); > } > > // get the data source from initial context > public DataSource getDataSource() throws NamingException { > > if (ds == null) { > > InitialContext ctx = new InitialContext(); > Context envCtx = (Context) > ctx.lookup("java:comp/env"); > ds = (DataSource) envCtx.lookup("jdbc/TestDB"); > > } > > return ds; > } > > // get the SQL connection from the database > public Connection getConnection() throws NamingException, > SQLException { > return getDataSource().getConnection(); > > } > > // execute particular database command > public Object executeDatabaseCommand(DatabaseCommand c) throws > Exception { > > Connection conn = null; > try { > conn = getConnection(); > Object o = c.executeDatabaseOperation(conn); > return o; > } catch (SQLException e) { > throw e; > } catch (NamingException ne) { > throw ne; > } finally { > if (conn != null) conn.close(); > } > } > } > > The DatabaseCommand has error. Move the cursor onto the name of > DatabaseCommand, an error message popup: > > DatabaseCommand cannot be resolved as a type > 3 quick fixes available: > . Add type parameter "DatabaseCommand" to "CommandExecutor" > . Add type parameter "DatabaseCommand" to > "executeDatabaseCommand(DatabaseCommand)" > . Fix Project Setup... > > I think I need to choose the third option "Fix Project Setup". > > Now, from Java Build Path, under the Source menu tab, it has the the > following layout: > DBTest/src > Included: (All) > Excluded: (None) > Native librarylocation (None) > > Look back the very beginning of this post, you can see the class file > DatabaseCommand.java file is already defined in the same directory as as > CommandExecutor.java defined. > > How to tell Eclipse compiler that the DatabaseCommand class is in the > same > directory as the CommandExecutor.java? > > Thanks > Sam > > --------------------------------------------------------------------- > To start a new topic, e-mail: users@tomcat.apache.org > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] >
