my requirement is to create a application specific xml file.
am i making any mistake here?

On Thu, Aug 21, 2008 at 2:35 AM, Luca Cicale <[EMAIL PROTECTED]> wrote:

> A simple way is to put in your web application a file named context.xml in
> META-INF directory, with the following content:
> <?xml version="1.0" encoding="UTF-8"?>
> <Context path="/reporting-application" />
>
> then you can produce your war and deploy it as usually (a simple way is to
> place it in your webapp directory in default tomcat6 configuration)
>
> Tomcat6 will make the rest of the job for you.
>
> Regards
> Luca Cicale
>
> --------------------------------------------------
> From: "Sushil Dodake" <[EMAIL PROTECTED]>
> Sent: Thursday, August 21, 2008 9:04 AM
> To: <users@tomcat.apache.org>
> Subject: [programmazione] how to set context path on TOMCAT6
>
>
> hi all,
>> I am using TOMCAT 6.
>> i have a application war file named as 'aaa.0.0.1d.war'
>> i need to set a context path for this application as
>> '/reporting-application'
>> so for this to work i am creating a xml file 'reporting-application.xml'
>> and
>> deploying it in the conf/Catalina/locahost/ direcotry.
>> the XML file content looks as below
>>
>> <?xml version="1.0" encoding="UTF-8"?>
>> <!-- Context fragment for deploying the build-demo application
>>
>> -->
>> <Context path="/reporting-application" docBase="..\webapps\aaa.0.0.1d.war"
>> />
>>
>> i followed the instructions given on the link
>> http://tomcat.apache.org/tomcat-6.0-doc/config/context.html
>> but i am seem to be missing somthing as i cant run my application using a
>> URL
>>
>>
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