André Warnier wrote: > Len Popp wrote: >> No, when a browser sends a POST request the request params are *not* >> sent as part of the request URI. They are sent in the body of the >> request. With Content-Type: application/x-www-form-urlencoded the >> request body looks like this: >> >> param1=a¶m2=b >> >> You can use a browser plugin such as LiveHTTPHeaders or ieHTTPHeaders >> to look at the contents of the request and make sure the parameters >> are in the request body. >> > I did, and you're right, I stand corrected. > It is clearly explained here : > http://www.w3.org/TR/html401/interact/forms.html#h-17.13.3.3 > Step four: Submit the encoded form data set > > and it becomes a lot clearer once you know what it means of course. > ;-) > > So, a follow-up question : > if you do a request.getInputStream(), do you get the body "raw" ? > (meaning you them have to do your own decoding of the parameters ?)
Yes. Unless you (or a filter, or a valve - the request dumper valve is often a culprit here) call getParameter() first. Mark --------------------------------------------------------------------- To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
