Greetings,

I've got a CentOS5 box with the standard CentOS5 tomcat5 and jvm packages 
installed.

$ rpm -qa | grep tomcat
tomcat5-jsp-2.0-api-5.5.23-0jpp.3.0.2.el5
tomcat5-admin-webapps-5.5.23-0jpp.3.0.2.el5
tomcat5-common-lib-5.5.23-0jpp.3.0.2.el5
tomcat5-servlet-2.4-api-5.5.23-0jpp.3.0.2.el5
tomcat5-jasper-5.5.23-0jpp.3.0.2.el5
tomcat5-server-lib-5.5.23-0jpp.3.0.2.el5
tomcat5-5.5.23-0jpp.3.0.2.el5

$ rpm -qa | grep java
gcc-java-4.1.2-14.el5
java-1.4.2-gcj-compat-1.4.2.0-40jpp.112
java-1.4.2-gcj-compat-devel-1.4.2.0-40jpp.112

I'm trying to make-it-go, but so far no dice. Connections to 
http://x.x.x:8080/admin get me to a login screen but no username/password 
combination seems to authenticate. Does anyone know what the default 
username/password are for an out-of-the-box install like this?

I've noticed in the logs that it also opens port 8009. However, connections 
there lead to a blank screen, and the following cryptic error message in 
/var/log/tomcat5/catalina.out:

24-Apr-08 1:40:13 AM org.apache.jk.common.MsgAjp processHeader
SEVERE: BAD packet signature 18245
24-Apr-08 1:40:13 AM org.apache.jk.common.ChannelSocket processConnection
SEVERE: Error, processing connection
java.lang.IndexOutOfBoundsException
   at java.io.BufferedInputStream.read(libgcj.so.7rh)
   at org.apache.jk.common.ChannelSocket.read(tomcat-ajp-5.5.23.jar.so)
   at org.apache.jk.common.ChannelSocket.receive(tomcat-ajp-5.5.23.jar.so)
   at 
org.apache.jk.common.ChannelSocket.processConnection(tomcat-ajp-5.5.23.jar.so)
   at 
org.apache.jk.common.ChannelSocket$SocketConnection.runIt(tomcat-ajp-5.5.23.jar.so)
   at 
org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(tomcat-util-5.5.23.jar.so)
   at java.lang.Thread.run(libgcj.so.7rh)

I've googled the snot out of "SEVERE: BAD packet signature 18245". Plenty of 
hits, but nothing explaining the message or its meaning.

Peter-Frank Spierenburg.

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