Hi All,
I am very bew to Linux and I have been given a task to integrate Apache and
Tomcat.
I got a document and integrated but the output I am getting is [B]It
works[/B].
I want to get my home page with my IP. but If I give Ip followed by
7080(full URL) I am able to see the home page.
I used jakarta-tomcat-connectors-jk2-2.0.4-src.tar.tar and
libtool-1.5.8.tar.tar.
jk2.properties:
[CODE]
channelSocket.port=8009
channelSocket.address=127.0.0.1
channelSocket.maxThreads=300[/CODE]
httpd.conf
I have added these lines..
[CODE]LoadModule jk2_module libexec/mod_jk2.so
<Location "/AjaxSample">
JkUriSet worker ajp13:127.0.0.1:8009
</Location>
<Location "/AjaxSample/*">
JkUriSet worker ajp13:127.0.0.1:8009
</Location>[/CODE]
workers2.properties
[CODE][shm]
file=/usr/local/apache2/logs/shm.file
size=1048576
# socket channel
[channel.socket:localhost:8009]
port=8009
host=127.0.0.1
# worker for the connector
[ajp13:localhost:8009]
channel=channel.socket:localhost:8009[/CODE]
server.xml
[CODE]<Host name="192.168.139.202:7080">
<Context path="/AjaxSample"
docBase=" /home/oracle/apache-tomcat-5.5.20/webapps/AjaxSample "
debug="0"
reloadable="true" crossContext="true"/>
</Host>[/CODE]
Is there any configuration I missed, please help me out.
Regards,
Kranthi Kiran
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