Re: Class is not a servlet

[David Smith]

I highly recommend reading the servlet spec.  There you will see a 
servlet extends HttpServlet and overrides one or more of it's methods.

http://jcp.org/en/jsr/detail?id=154
--David

Luca Sabbio wrote:

Hi, I'm working with Java 1.5.0.06, Tomcat 5.5.16 with Xindice 1.1b4 and Cocoon 
2.1.10 deployed (and working).

I try to run a simple web application based on a servlet that update the 
Xindice XML DB
By the command line the PartsXupdate.java is compiled and the 
PartsXupdate.class works.

import org.xmldb.api.base.*;
import org.xmldb.api.modules.*;
import org.xmldb.api.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;


public class PartsXupdate {
  public static void main(String[] args) throws Exception {
     Collection col = null;
     try {
        String driver = "org.apache.xindice.client.xmldb.DatabaseImpl";
        Class c = Class.forName(driver);
        
        Database database = (Database) c.newInstance();
        DatabaseManager.registerDatabase(database);
        
        col = DatabaseManager.getCollection("xmldb:xindice://localhost:8080/db/test");
        
String xupd = "<xupdate:modifications version=\"1.0\" xmlns:xupdate=\"http://www.xmldb.org/xupdate\";>"  + 
"<xupdate:insert-after select=\"/scheda/info\">"  +
"<xupdate:element name=\"commento\">Bel libro!</xupdate:element>"  + 
"</xupdate:insert-after>"  + 
"</xupdate:modifications>"; 



   String nome = "4.xml";   

           /* We are using XUpdateQueryService */
           XUpdateQueryService service =
              (XUpdateQueryService) col.getService("XUpdateQueryService", 
"1.0");
              
           service.updateResource(nome, xupd);
     }
     catch (XMLDBException e) {
        System.err.println("XML:DB Exception occurred " + e.errorCode);
     }
     finally {
         if (col != null) { col.close();}
     }
  }
}

But when I deploy the application on Tomcat 
and I do my post action http://localhost:8080/PartsXupdate/PartsXupdate from the form of provajava.html 
I get this error:
javax.servlet.ServletException: Class PartsXupdate is not a Servlet

I think that my web.xml is ok

<?xml version="1.0" encoding="ISO-8859-1"?>

<web-app xmlns="http://java.sun.com/xml/ns/j2ee";
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
   xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd";
   version="2.4">

 <display-name>esempio_servlet_xupdate</display-name>
 <description>
    Esempio di uso di servlet_xupdate
 </description>

<!-- JSPC servlet mappings start -->

<servlet>
       <servlet-name>PartsXupdate</servlet-name>
       <servlet-class>PartsXupdate</servlet-class>
   </servlet>

   <servlet-mapping>
       <servlet-name>PartsXupdate</servlet-name>
       <url-pattern>/PartsXupdate</url-pattern>
   </servlet-mapping>

<welcome-file-list>
 <welcome-file>provajava.html</welcome-file>
</welcome-file-list>

</web-app>

Also classpath would be ok. Is there something to set in Tomcat?
I've read many mailing list and tried some changes but without results,
any suggestion would be appreciate.
Thanks
 



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