Hi Thank you for reading my post. I need to pass a parameter like : -javaagent:%INFRARED_HOME%\aspectjweaver-1.5.0.jar to tomcat startup. the tutorial talks about a bat file that we can add this parameter to it but Tomcat 5.5.17 for windows does not has any +batch file. It just has two executable files named tomcat.exe and tomcatW.exe . I have tried to add the parameter in java tab after
-Dcatalina.home=f:\dev\apps\Tomcat 5.5.17 -Dcatalina.base=f:\dev\apps\Tomcat 5.5.17 -Djava.endorsed.dirs=f:\dev\apps\Tomcat 5.5.17\common\endorsed -Djava.io.tmpdir=f:\dev\apps\Tomcat 5.5.17\temp -Djava.util.logging.manager=org.apache.juli.ClassLoaderLogManager -Djava.util.logging.config.file=f:\dev\apps\Tomcat 5.5.17\conf\logging.properties But when i add that parameter here, tomcat does not start. can you please tell me where and how i should add that parameter ? Thanks -- View this message in context: http://www.nabble.com/how-to-pass-a-parameter-to-tomcat-startup-in-windows--tf3275543.html#a9109294 Sent from the Tomcat - User mailing list archive at Nabble.com.
