> From: David Schulberg [mailto:[EMAIL PROTECTED] 
> Subject: RE: Starting Tomcat
> 
> F:\apache-tomcat-5.5.20\bin>catalina run
> Using CATALINA_BASE:   F:\apache-tomcat-5.5.20
> Using CATALINA_HOME:   F:\apache-tomcat-5.5.20
> Using CATALINA_TMPDIR: F:\apache-tomcat-5.5.20\temp
> Using JRE_HOME:        C:\Program Files\Java\jdk1.5.0_07
> "C:\Program Files\Java\jdk1.5.0_07\bin\java" 
> -Djava.util.logging.manager=org.ap
> ache.juli.ClassLoaderLogManager
> -Djava.util.logging.config.file="F:\apache-tomca
> t-5.5.20\conf\logging.properties"  
> -Djava.endorsed.dirs="F:\apache-tomcat-5.5.2
> 0\common\endorsed" -classpath "C:\Program
> Files\Java\jdk1.5.0_07\lib\tools.jar;F
> :\apache-tomcat-5.5.20\bin\bootstrap.jar"
> -Dcatalina.base="F:\apache-tomcat-5.5.
> 20" -Dcatalina.home="F:\apache-tomcat-5.5.20"
> -Djava.io.tmpdir="F:\apache-tomcat
> -5.5.20\temp" org.apache.catalina.startup.Bootstrap  start

In order to get the above, someone must have modified catalina.bat to
display the generated command, perhaps by putting an echo at the front
of the line (193 in the unedited script).  Doing so would prevent the
command from being executed.

> I would have thought it would be firing up tomcat5w.exe or tomcat.exe

No, those are only used for the service.  When running from a command
prompt, a direct call to the standard java launcher is used.

 - Chuck


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