Did you reload the webapp after making the change? All changes to
WEB-INF/web.xml or files in WEB-INF/classes and WEB-INF/lib will require
a reload before they become active in tomcat.
--David
McRaven, Brian wrote:
I was able to refer to a book I have and so I dropped the .class
extensions altogether. I get an error that requested resource is not
available still. Any suggestions on this? My web.xml file has this
entry:
<servlet>
<servlet-name>JustALittleTest</servlet-name>
<servlet-class>JustAlittleTest</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>JustALittleTest</servlet-name>
<url-pattern>/JustALittleTest</url-pattern>
</servlet-mapping>
And my action attribute="JustALittleTest".
Brian
-----Original Message-----
From: McRaven, Brian
Sent: Tuesday, July 11, 2006 1:14 PM
To: users@tomcat.apache.org
Subject: Accessing a servlet
Well I'm ticking these newbie questions off. I have a simple servlet
that I want my form to access. I compiled the file fine and it is
called JustALittleTest.class. I placed this file in the
ROOT/WEB-INF/classes folder. In my JSP I have a form with some submit
buttons. The action element of the form is set to ="JustALittleTest".
I changed my web.xml file so it now has the following entries:
<servlet>
<servlet-name>JustALittleTest</servlet-name>
<servlet-class>JustAlittleTest.class</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>JustALittleTest</servlet-name>
<url-pattern>/JustALittleTest.class</url-pattern>
</servlet-mapping>
I've tried a few changes to the above entries but I haven't gotten it
right yet. Should the servlet-class value have a .class extension? Is
my url pattern accessing the correct folder?
Brian
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