On 02/12/2019 04:53, Kushagra Bindal wrote:
> Hi Mark,
> 
> Please find the snippet from web.xml

Which URL pattern do you expect:

"http://backend_tomcat:8080/sdm/restcall/v1/platform//healthCheck";

to match?

And what is the Context Path at which the application is deployed?

Mark


> 
> <servlet>
>         <servlet-name>default</servlet-name>
> 
> <servlet-class>org.apache.catalina.servlets.DefaultServlet</servlet-class>
>         <init-param>
>             <param-name>debug</param-name>
>             <param-value>0</param-value>
>         </init-param>
>         <init-param>
>             <param-name>listings</param-name>
>             <param-value>false</param-value>
>         </init-param>
>         <load-on-startup>1</load-on-startup>
>     </servlet>
>     <servlet>
>         <servlet-name>jsp</servlet-name>
>         <servlet-class>org.apache.jasper.servlet.JspServlet</servlet-class>
>         <init-param>
>             <param-name>fork</param-name>
>             <param-value>false</param-value>
>         </init-param>
>         <init-param>
>             <param-name>xpoweredBy</param-name>
>             <param-value>false</param-value>
>         </init-param>
>         <load-on-startup>3</load-on-startup>
>     </servlet>
>    <!-- The mapping for the default servlet -->
>     <servlet-mapping>
>         <servlet-name>default</servlet-name>
>         <url-pattern>/</url-pattern>
>     </servlet-mapping>
>     <!-- The mappings for the JSP servlet -->
>     <servlet-mapping>
>         <servlet-name>jsp</servlet-name>
>         <url-pattern>*.jsp</url-pattern>
>         <url-pattern>*.jspx</url-pattern>
>     </servlet-mapping>
>      <servlet>
>       <servlet-name>PatternTemplateLaunchServlet</servlet-name>
>       <servlet-class>PatternTemplateLaunchServlet</servlet-class>
>    </servlet>
>    <servlet>
>       <servlet-name>MyReportsLaunchServlet</servlet-name>
>       <servlet-class>MyReportsLaunchServlet</servlet-class>
>    </servlet>
>    <servlet-mapping>
>       <servlet-name>PatternTemplateLaunchServlet</servlet-name>
>       <url-pattern>/patterntemplatelaunch</url-pattern>
>    </servlet-mapping>
>    <servlet-mapping>
>       <servlet-name>MyReportsLaunchServlet</servlet-name>
>       <url-pattern>/MyReportsLaunchServlet</url-pattern>
>    </servlet-mapping>
> 
> Please let me know if you need anyother details from our side.
> 
> On Mon, Dec 2, 2019 at 3:07 AM Mark Thomas <ma...@apache.org> wrote:
> 
>> On 01/12/2019 07:11, Kushagra Bindal wrote:
>>> Hi Manna/Mark,
>>>
>>> Below are the sample URL which we are passing to Tomcat.
>>>
>>> http://backend_tomcat:8080//sdm/restcall)(.*)/file_uploads
>>> http://backend_tomcat:8080/sdm/restcall/v1/platform//healthCheck
>>>
>>> As from the above example you can see that // location may vary case by
>>> case.
>>>
>>> So, you guys have a probable solution to handle such situation, then
>> please
>>> do let me know.
>>
>> Tomcat is simply going to normalize those to single '/'. The application
>> should be fine with that.
>>
>> To repeat my previous request:
>> Can you provide more details such as:
>> - an example request URI
>> *and*
>> - the <url-pattern> for the servlet you expect it to match to
>>
>> Mark
>>
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> 


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