You can put the path in an <init-param> in the application's web.xml. Then
retrieve it at runtime in your servlet.init() method using
getInitParameter("path").
On 5/15/06, Calvin Deiterich <[EMAIL PROTECTED]> wrote:
I need to place a file(.xsl) in with a tomcat servlet application and
I do not want to hard-code the path into the java code. I want the
file to be in the \webapps\<projectname>\WebContent\xml\xslt\ path.
What is the best way to handle this.
Thanks
Calvin
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