Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
Hi.
On this list, the convention is to not "top post".
Put your answers either in-line, in the text, or at the end.
That is much easier for others to follow the conversation in a logical order.
Anil Goyal -X (anigoyal - Aricent Technologies at Cisco) wrote:
Thanks for the reply Andre.....
Let me explain you in detail.
Let's suppose we have two applications App1.war and App2.war, deployed in
webapps of tomcat.
Now I want only App2 to listen additionally on a separate connector port(lets
suppose 8181) along with port 8080 to which it is already listen.
But I want App1 to listen only on port 8080 not on port 8181.
So what I did, I create a new service in tomcat with name 'catalina_new' and
appBase='webapps_new' and I add a connector port 8181 in this.
Now I deploy my App2.war in webapps_new.
So after restart the tomcat, I am able to make App2 to listen on port 8080 as
well as port 8181(since App2.war is present in both webapps and webapps_new),
and App1 is listen on only port 8080.
Till now, everything was fine.
Now I do not want to have a separate appBase for service
'catalina_new', means I want appBase='webapps' for service 'catalina_new' as well So by doing this change, my App1 also starts listen on port 8181 which is not required.
So what can I do to make only App2 to listen on new port under new service with 'appBase=webapps'
Hope you understand my query now!
I do understand, approximately. But honestly, your way of thinking about this
is different from mine, and I have some trouble following your idea.
This may also be because my knowledge of the inner workings of Tomcat is
limited, and I am not even sure that what you are currently doing is even
supposed to work.
In my understanding, what is "listening" on a given port is not a webapp, it is
Tomcat.
Tomcat accepts a connection on one of the ports that it is listening to,
through one of the Connector elements of that Tomcat.
(Until now, the webapps are not involved at all) Then Tomcat allocates this
connection to a Thread, to process the HTTP request which has been written by
the client to that connection.
Then the Thread reads the HTTP request line sent by the client, and the HTTP
request header lines.
(Until now, the webapps are not involved at all) Then the Thread reads the "Host:" header
line in that request, and determines to which <Host> this request is addressed. Then the
Thread loads the appropriate configuration for that <Host>, before processing the request any
further.
(Until now, the webapps are still not involved at all)
*Now* the Thread knows that for this <Host>, the active applications are located
somewhere, and it knows to which "context path" each application should be answering.
So *now* the Thread can call the appropriate webapp and give it the incoming
request to process.
So *now* one of the active webapps is involved.
And at this point, it could be any webapp that is active within that <Host>.
What I am trying to say, is that the selection of the port on which a request
comes in is not controlled by the webapp, and cannot be. It is done much
earlier in the cycle, and depends only on to which port the client connects and
sends his request on.
At the moment Tomcat accepts such a request, it does not know yet neither the <Host>,
nor the webapp within the <Host>, which this client wants. And it cannot at that
point decide to accept or refuse this request depending on which webapp it will ultimately
go to, because it does not know that yet.
I must confess that I do not really know if your idea of doing this by having 2
<Service> elements in Tomcat may or may not provide a way to overcome this.
But to me, at this point, the idea seems a bit strange.
To say the truth, I don't even know if your basic idea to restrict the access
to a webapp based on which port the request comes in, makes really sense for
what your basic issue is.
But if that is really the issue, then I would do this on the base of a servlet
filter configured for that webapp.
You could probably use the urlrewrite filter (http://tuckey.org/urlrewrite/)
for that, which would be much easier than your current setup.
The flow that you explain is absolutely fine and even I have the same flow in
my mind as well.
As you know there is one param 'deployIgnore' in Host Configuration. Can't we
use that one for that.
As I already explained you earlier that the case is regarding the two services
in tomcat pointing to same appBase. If we add connector port lets suppose 8080
in service 1 and 8181 in service 2 then what will happen if I hit the url
http://ip-address:8080/App1
http://ip-address:8080/App2
http://ip-address:8181/App1
http://ip-address:8181/App2
It will give 200 Ok response in all the cases .
Now what if with port 8181, I want to access App1 only means now what I want is
http://ip-address:8080/App1 should be 200OK
http://ip-address:8080/App2 should be 200OK
http://ip-address:8181/App1 should be 200OK
http://ip-address:8181/App2 should be 404 Error
To achieve this, what I want to do in server.xml of tomcat.
How can I achieve that App1 should be accessible from both the ports 8080 and
8181, App2 should be accessible from 8080 not 8181.
I think we can add deployIgnore="App2" in Host configuration of new service in server.xml to make App2 not accessible at new port 8181
What you suggest??
I will repeat what I said before : I think the way that you are thinking about this (with
the second <Service>) is too complicated, and may trigger side-effects that you do not expect.
What I would do is :
- use a normal Tomcat installation, with one Service etc..
- deploy your webapp1 and webapp2 applications normally
- however, in webapp2, add a servlet filter (urlrewritefilter), and in that filter you
/can/ test on which port the request came in, and then return a 404 error if it is not the
port that you want.
The additional advantage is that this kind of setup is totally standard for a java servlet
container, and servlet filters are standard for all servlet containers. So this
configuration would be totally portable.
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