Hi,
I've been struggling recently with this builtin valve and some
Spring-based REST services. I some cases I do return states like 404 or
400. SendError seems to be the right thing to do but Tomcat alters the
response with the HTML page. Which is highly unwanted for a REST API.
I have checked Oracle's original JavaDocs for #sendError(int) + Servlet
Spec 2.5 and 3.0 all three of them, do not explicitly mention that an
error HTML response is returned with this method. The JavaDoc [1] says:
"...If an error-page declaration has been made for the web application
corresponding to the status code passed in, it will be served back the
error page..."
I did not define a custom error page.
Where as the #sendError(int,String) says:
"... The server defaults to creating the response to look like an
HTML-formatted server error page containing the specified message,
setting the content type to "text/html"."
This one is crystal clear.
sendError(int) simply calls sendError(int,String) with a null string arg.
Am I misunderstanding the the definition? Should I avoid sendError
alltogher and resort to setStatus? What would be the implications?
I do know that sendError commits and closes the response immediately.
A clarification is highly appreciated.
Thanks,
Michael
[1]
http://docs.oracle.com/javaee/6/api/javax/servlet/http/HttpServletResponse.html#sendError%28int%29
---------------------------------------------------------------------
To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org
For additional commands, e-mail: users-h...@tomcat.apache.org
