Basically I have a question ,If the request is made from multihomed machine ,which IPaddress will be taken as clients's IPaddress?. Does it is configurable or how it decides that ?
Its becoz , I have multihomed machine with 2 IPaddr x.x.x.17 and x.x.x.18 . Since InetAddress.getLocalHost returns x.x.x.18 . I expects client originated from same machine and it's request.getRemoteAddr should also return x.x.x.18 .Where as it returns value as x.x.x.17 Can someone tell me how can I get resolve this . ~Mani On 4/6/06, Markus Schönhaber <[EMAIL PROTECTED]> wrote: > > manikandan mvk wrote: > > I have a machine with multihomed interface . basically , I am making > call > > where both the server and client are same machine . Here , I am trying > to > > validate the IPaddress from the request with InetAddress.getLocalHost() . > > Since ,both the client and server are same machine . I expects > > httpservletrequest.getRemoteAddr() should be equals > > InetAddress.getLocalHost().getHostAddress();But Its not the case .. > > > > i.e ; > > In my multihomed machine : IPaddress of interface hme0 is : x.x.x.17 > and > > IPaddress of interface hme0:1 is :x.x.x.18 > > Hostname of the machine is mapped to x.x.x.18 . > > > > Here , request.getRemoteAddr() returns x.x.x.17 ,whereas > > netAddress.getLocalHost().getHostAddress() returns x.x.x.18 . > > > > I feels request.getRemoteAddr() should also return x.x.x.18 . > > request#getRemotesAddr() should return the address the request was made > from. > Which address does your client use to send the request from? > > Regards > mks > > --------------------------------------------------------------------- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > >
