char is a numeric type. You might try this code as an example: char c = 32; c += '@'; if(c > 31) System.out.println(c + " = " + (int)c);
The exception is it adds to strings as a character, thus the cast is needed. Regards, Artur --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
