It is because no servlet is selected for that url based on both explicit
and implicit servlet mappings. You would need to pre-compile the jsp
into class file (e.g. basic-arithmetic_jsp.class) and then define and
map the servlet:
<servlet-mapping>
<servlet-name>basic-arithmetic_jsp</servlet-name>
<url-pattern>/basic-arithmetic.jsp/*</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>basic-arithmetic_jsp</servlet-name>
<servlet-class>basic-arithmetic_jsp.class</servlet-name>
</servlet>
Using this configuration, /test will be passed to your servlet as
request path info.
You can take a look of section 11.2 of the servlet specification for
details.
-----Original Message-----
From: Xiangzhou Wang [mailto:[EMAIL PROTECTED]
Sent: Wednesday, February 22, 2006 4:31 PM
To: users@tomcat.apache.org
Subject: tomcat 5.5.15 404 - extra path after jsp page
I am using tomcat 5.5.15, I can access jsp page, but if I put /something
after jsp page, I will get 404 error.
e.g.
good ->
http://localhost:8080/jsp-examples/jsp2/el/basic-arithmetic.jsp
error->
http://localhost:8080/jsp-examples/jsp2/el/basic-arithmetic.jsp/test
Is there a way to still access the jsp and use getPathInfo to get
"test"? change config ??
Thanks,
William
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