Hi Josh,

Yup, it must be. The question is, how do I stop that? I tried following the
example from the jumpstart demo but it didn't work, and I tried setting the
version field manually, and it still didn't work (the exact code I used is
in the initial email).

On Sun, May 29, 2011 at 12:11 PM, Josh Canfield <joshcanfi...@gmail.com>wrote:

> I would guess that you are pulling the object from the database when you
> post the form, and thus editing the current version.
>
> I believe is the default behaviour with the tapestry persistent object
> translator, it stores the type and id in the form.
>
> Josh
> On May 29, 2011 7:34 AM, "Donny Nadolny" <donny.nado...@gmail.com> wrote:
> > I've got a BeanEditForm for my User entity which has a version field:
> >
> > @Version
> > public long getVersion() {
> > return version;
> > }
> > public void setVersion(long version) {
> > this.version = version;
> > }
> >
> > I've got an admin screen to edit a user, and I would like to make sure I
> > don't overwrite changes made by the user (they can change their password,
> > for example) or by the application, while I'm on the edit screen. I've
> tried
> > a few things, but I always see the same behavior: any changes in the
> > database get overwritten when I hit "save" in the BeanEditForm.
> >
> > Test 1:
> > EditUser.tml:
> > <t:BeanEditForm object="user" t:id="editUserForm"/>
> >
> > EditUser.java:
> > @CommitAfter
> > public Object onSuccessFromEditUserForm() {
> > return UserIndex.class;
> > }
> >
> > I open the EditUser page in the browser, I change the user in the
> database
> > (increasing the version field by one), then I hit save in the browser,
> > expecting Hibernate to throw an exception. Instead, it saves the changes,
> > increasing the version again. Eg I start at version 0, open the page,
> edit
> > the db to change a field and set version to 1, then I hit save in the
> > browser, it clobbers my changes and sets version to be 2.
> >
> >
> > Test 2:
> > I tried out the code from JumpStart
> >
>
> http://jumpstart.doublenegative.com.au/jumpstart/examples/easycrud/update/2which
> > says it handles versioning. My code now looks like this:
> > tml:
> > <t:BeanEditForm object="user" t:id="editUserForm">
> > <p:version>
> > <t:hidden value="user.version"/>
> > </p:version>
> > </t:BeanEditForm>
> >
> > The java code is the same as Test 1.
> >
> > Again, the changes get clobbered.
> >
> > Test 3:
> > I noticed that the hidden field didn't have an ID set, so I tried:
> > <t:hidden value="user.version" t:id="version"/>
> > Same thing, changes get overwritten.
> >
> > Test 4:
> > Managing the version myself. In the tml I have:
> > <t:BeanEditForm object="user" t:id="editUserForm">
> > <p:version>
> > <t:hidden t:id="versionWhenLoaded"/>
> > </p:version>
> > </t:BeanEditForm>
> >
> > In java, I have:
> > @PageActivationContext
> > private User user;
> >
> > @Property
> > private long versionWhenLoaded;
> >
> > public void setupRender() {
> > versionWhenLoaded = user.getVersion();
> > }
> >
> > @CommitAfter
> > public Object onSuccessFromEditUserForm() {
> > user.setVersion(versionWhenLoaded);
> > return UserIndex.class;
> > }
> >
> > Again, changes get overwritten. I really would expect the last case to
> work
> > - maybe I need to do something special in Hibernate to set the version
> > field?
> >
> > I'm using tapestry 5.2.4, the tapestry-hibernate dependency (so Hibernate
> > 3.6.0-Final).
> >
> > I've confirmed that Hibernate does throw a
> > StaleObjectStateExceptionexception when it tries to make changes to
> > the user at the same time, by
> > having another page which does, essentially:
> > User user = userDAO.findById(1);
> > timeProvider.sleep(10000);
> > user.setFirstName("something different");
> > sessionManager.commit();
> > I load it twice, and the second page throws StaleObjectStateException.
> >
> > Any ideas?
>

Reply via email to