hi bobharner ,

I have seen whatever link you sent to me.But there clearly mention you can 
take any name instead of app.anyway i changed it app1 to app as you said and
run the application but i am still getting same exception.

By convention, the filter name (filter-name) is almost always "app", but you
can use any name you want. Tapestry uses this to determine what module class
name to look for .


Please find solution,
Thanks in Advance
Raj Jaiswal
MCA SCJP1.6



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