Em Sat, 09 Jan 2010 15:09:30 -0200, Everton Agner
<everton_ag...@yahoo.com.br> escreveu:
Hi,
Hi!
How can I do that? I haven't found anything about that. I only know that
if I add one column to the Grid in the "add" attribute (or directly at
it's BeanModel), it will not be part of the Sorting.
@Inject BeanModelSource to create a BeanModel yourserf. Then:
final List<String> propertyNames = model.getPropertyNames();
for (String propertyName : propertyNames) {
model.get(propertyName).sortable(false);
}
Then pass this BeanModel instance to the model parameter of the Grid
component. ;)
--
Thiago H. de Paula Figueiredo
Independent Java, Apache Tapestry 5 and Hibernate consultant, developer,
and instructor
Owner, software architect and developer, Ars Machina Tecnologia da
Informação Ltda.
http://www.arsmachina.com.br
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