Thanks, but I am not sure how to do that in a dispatcher.
-Borut
2009/4/23 Howard Lewis Ship <hls...@gmail.com>:
> You can return a StreamResponse whose job is to generate an
> InputStream of XML to be sent to the client.
>
> On Thu, Apr 23, 2009 at 6:12 AM, Borut Bolčina <borut.bolc...@gmail.com>
> wrote:
>> Hello,
>>
>> I have a dispatcher which matches some URL pattern like this:
>>
>> public boolean dispatch(Request request, Response response) throws
>> IOException {
>> String path = request.getPath();
>> // just imagine this works ok
>> String uglyWord = request.getContextPath() == "" ?
>> StringUtils.substringAfterLast(path, "/") : path.substring(1);
>>
>> if (uglyWordSet.contains(uglyWord)) {
>> // return some XML if url contains some ugly word
>> // WHAT IS THE BEST APPROACH TO RETURN XML (STREAM) ?
>> return true;
>> }
>>
>> return false;
>> }
>>
>> I know how to create a page which returns xml stream response (I
>> actually have one). Can I just reuse this page?
>>
>> Using T 5.0.18.
>>
>> Regards,
>> Borut
>>
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>>
>
>
>
> --
> Howard M. Lewis Ship
>
> Creator of Apache Tapestry
> Director of Open Source Technology at Formos
>
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