Hello Anna. Agreed. It's a little bit counterintuitive, but described explicitly in the braced note here https://lucene.apache.org/core/9_7_0/core/org/apache/lucene/search/BooleanQuery.Builder.html#setMinimumNumberShouldMatch(int)
To achieve what you need > set to 0, meaning that all clauses are optional. you can combine the dismax with match all query *:* On Thu, Jan 4, 2024 at 4:43 PM Anna Ruggero <a.rugg...@sease.io> wrote: > Hi everyone, > > I have this query that uses the Boolean Query Parser: > *http://localhost:8983/solr/books/select > <http://localhost:8983/solr/books/select>?* > *q={!bool filter=$**categoryIds** should=$queryTerms}&* > *categoryIds**=**category:(1 2 5 7)**&* > *queryTerms=**content**:(user text)* > > I would like to achieve the same result using the eDisMax query parser, but > I encountered some problems with the minimum should match clause. > > Here is the query: > *http://localhost:8983/solr/books/select > <http://localhost:8983/solr/books/select>?* > *fq=category:(1 2 5 7)&* > *q=user text&* > *df=content&* > *defType=edismax* > > It returns only documents having "*user"* or "*text"* in the content field > (but at least one of them is needed). If no documents contain those words > in the *content* field, I have zero results returned. > From the debug, I could see that the parsed query is: > *+(DisjunctionMaxQuery((**content**:user)) DisjunctionMaxQuery((**content* > *:text)))* > > By default the minimum should match parameter is set to 0, meaning that all > clauses are optional. Why is there the + operator before the two > disjunction queries? I wouldn't expect to see it. I would expect to see all > documents returned even if none of them match any term in q. > > Also, if I explicitly set mm to 1 like: > *http://localhost:8983/solr/books/select > <http://localhost:8983/solr/books/select>?* > *fq=category:(1 2 5 7)&* > *q=user text&* > *df=content&* > *defType=edismax&* > *mm=1* > > The parsed query is: > *+(DisjunctionMaxQuery((**content**:**user**)) DisjunctionMaxQuery((* > *content**:**text* > *)))~1* > Whose meaning is the same as the query before (with mm=0). > > What is the difference between mm=0 and mm=1? > > > Thank you! > > *Anna Ruggero* > R&D Machine Learning / Software Engineer, Search Consultant > e-mail: a.rugg...@sease.io > > > *Sease* - Information Retrieval Applied > Consulting | Training | Open Source > Sease.io <http://sease.io/> > LinkedIn <https://linkedin.com/company/sease-ltd> | Twitter > <https://twitter.com/seaseltd> | Youtube > <https://www.youtube.com/channel/UCDx86ZKLYNpI3gzMercM7BQ> | Github > <https://github.com/seaseltd> > -- Sincerely yours Mikhail Khludnev
