Hi,
if I remember correctly, the {!func} query parser just uses the function to
assign the score to the search results.
It won't make much sense to use it in a 'fq' parameter.
I agree it's not well documented though.You may be interested in the frange query parser instead: https://solr.apache.org/guide/8_8/other-parsers.html#function-range-query-parser . Aside from that, you may achieve the same with a simple range query: fq=-(popularity:[* TO *]) (make sure the query parser you use it, supports pure negative clauses. Cheers -------------------------- Alessandro Benedetti Apache Lucene/Solr Committer Director, R&D Software Engineer, Search Consultant www.sease.io On Fri, 25 Jun 2021 at 14:12, Rahul Goswami <rahul196...@gmail.com> wrote: > Hello, > I am using Solr 7.7.2. Below query is not returning expected results on the > sample "techproducts" core. > > > http://localhost:8983/solr/techproducts/select?debug=query&fq={!func}not(exists(popularity))&q=*:*&wt=json&rows=1 > > The query returns ALL documents in 'numFound' despite the 'not' function. > Result is the same even when with defType=edismax (although that should not > interfere since I am specifying the 'func' parser). > Does this warrant a JIRA? > > Thanks, > Rahul >
